Answer:
Inductor.
Explanation:
it is given that, the voltage across the device leads the voltage across a resistor at 500 Hz. The device that has unknown circuitry can be a inductor. For LC circuit, the voltage across the inductor leads the voltage across resistor. So, the device can be a inductor.
Answer:
Because if they dont research first they will be unprepared
Explanation:
Answer:633.8 KJ
Explanation:
Given
mass of water![\left ( m\right )=250gm](https://tex.z-dn.net/?f=%5Cleft%20%28%20m%5Cright%20%29%3D250gm)
Initial temperature![\left ( T_i\right )=20^{\circ}C](https://tex.z-dn.net/?f=%5Cleft%20%28%20T_i%5Cright%20%29%3D20%5E%7B%5Ccirc%7DC)
Final temperature ![\left ( T_f\right )=100^{\circ}C](https://tex.z-dn.net/?f=%5Cleft%20%28%20T_f%5Cright%20%29%3D100%5E%7B%5Ccirc%7DC)
Specific heat of water
=4190 J/kg-k
heat of vaporization![\left ( L\right )=22.6\times 10^5 J/kg](https://tex.z-dn.net/?f=%5Cleft%20%28%20L%5Cright%20%29%3D22.6%5Ctimes%2010%5E5%20J%2Fkg)
Heat required for process
=heat to raise water temperature from 20 to 100 +Heat to vapourize water completely
Q=mc![\left ( T_f-T_i\right )+mL](https://tex.z-dn.net/?f=%5Cleft%20%28%20T_f-T_i%5Cright%20%29%2BmL)
Q=![0.25\times 4190\times \left ( 100-20\right )+0.25\times 22\times 10^5](https://tex.z-dn.net/?f=0.25%5Ctimes%204190%5Ctimes%20%5Cleft%20%28%20100-20%5Cright%20%29%2B0.25%5Ctimes%2022%5Ctimes%2010%5E5)
Q=![\left ( 0.838+5.5\right )\times 10^5](https://tex.z-dn.net/?f=%5Cleft%20%28%200.838%2B5.5%5Cright%20%29%5Ctimes%2010%5E5)
Q=![6.338\times 10^5J=633.8 KJ](https://tex.z-dn.net/?f=6.338%5Ctimes%2010%5E5J%3D633.8%20KJ)
Answer:
Gravitational potential energy is due to the position of an object above Earth's surface. The object has the potential to fall due to gravity.
Explanation:
Gravitational potential energy depends on an object's weight and its height above the ground (GPE = weight x height). hope this helps you :)
From an energy balance, we can use this formula to solve for the angular speed of the chimney
ω^2 = 3g / h sin θ
Substituting the given values:
ω^2 = 3 (9.81) / 53.2 sin 34.1
ω^2 = 0.987 /s
The formula for radial acceleration is:
a = rω^2
So,
a = 53.2 (0.987) = 52.494 /s^2
The linear velocity is:
v^2 = ar
v^2 = 52.949 (53.2) = 2816.887
The tangential acceleration is:
a = r v^2
a = 53.2 (2816.887)
a = 149858.378 m/s^2
If the tangential acceleration is equal to g:
g = r^2 3g / sin θ
Solving for θ
θ = 67°