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ivanzaharov [21]
3 years ago
6

5.

Physics
1 answer:
igor_vitrenko [27]3 years ago
3 0

Answer:

a=40\ m/s^2

Explanation:

Given that,

Initial speed of a shuttlecock, u = 30 m/s

Final speed of the shuttlecock, v = 10 m/s

Time, t = 0.5 s

We need to find its average acceleration. The acceleration of an object is equal to the change in speed divided by time taken. It is given by :

a=\dfrac{v-u}{t}\\\\a=\dfrac{10-30}{0.5}\\\\a=-40\ m/s^2

So, the average acceleration of badminton shuttlecock is 40\ m/s^2.

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