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Damm [24]
3 years ago
6

What einstein discovered about space and time is that they?

Physics
1 answer:
svp [43]3 years ago
4 0
Einstein's...<span> theory of general relativity predicted that the </span>space-<span>time....</span>
You might be interested in
A driver in a car traveling at a speed of 50 mi/h sees a deer 50 m away on the road. Calculate the minimum constant acceleration
alisha [4.7K]

Answer:

a= - 0.79 m/s²

Explanation:

Given that

Speed ,u = 20 mi/h

We know that

1 mi/h= 0.44 m/s

Therefore ,u = 8.94 m/s

Distance ,s= 50 m

Lets take the acceleration of the car = a m/s²

The final speed of the car ,v = 0 m/s

We know that

v²= u² + 2 a s

Now by putting the values

0²= 8.94² + 2 x a x 50

a=-\dfrac{8.94^2}{2\times 50}\ m/s^2

a= - 0.79 m/s²

Therefore the acceleration will be - 0.79 m/s².

6 0
3 years ago
What processes were involved in the formation of the model? How is the model similar to the real sedimentary sample? How is the
Stels [109]

Answer:

1. sediment layering and compacting on top of each other and solidifying

2. sediment layering and compacting (not as much) on top of each other and solidifying, just not as much

Explanation:

hope this helps! :))

8 0
3 years ago
Convert 150 decameters to decimeters. Enter the answer.​
kotykmax [81]

Answer:

15,000 decimeters

Explanation:

1 decameter = 100 decimeters

150 * 100

15,000

Best of Luck!

5 0
3 years ago
Which of the following statements does not describe the structure of an atom?
Lynna [10]
D...because most of the mass of an atom comes from the nucleus so its not true so D is the correct answer
8 0
3 years ago
A heat engine with 0.500 mol of a monatomic ideal gas initially fills a 1000 cm3 cylinder at 700 K . The gas goes through the fo
Zarrin [17]

Answer:

2234.63

Explanation:

Work done per cycle by the engine is calculated as;

W=\int p \ dv

#Since volume doesn't change in the isochoric steps, there is no work done, hence:

W_2=W_3=0

#For an isothermal change of state(ideal gas):

pV=nRT\\\\W=P_iV_ i\int \frac{1}{V} \ dV\\\\=P_iV_ iIn(V_f/V_i)

#for the expansion process:

W_i=0.5mol\times8.3145J/molK\times 700K \ In(6000cm^3/1000cm^3)\\\\W_i=5214.15J

W_4=0.5mol\times8.3145J/molK\times 400K \ In(6000cm^3/1000cm^3)\\\\W_4=-2979.52

W=W_1+W_2+W_3+W_4\\\\=5214.15J-2979.52\\\\=2234.63J

Hence, the engine does 2234.63J per second.

8 0
3 years ago
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