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kotykmax [81]
3 years ago
10

What are greenhouse gases? Can you name any?

Physics
1 answer:
svp [43]3 years ago
7 0
Greenhouse gasses in the upper atmosphere trap heat from the Earth and reflect it back down rather than allow it to escape. This makes Earth progressively warmer.
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PLEASE I'M GOING TO FAIL HELPPPP
BaLLatris [955]
I think the answer is E
4 0
3 years ago
Write a script that depicts an employer meeting expectation and failing meeting expectations
Aleks04 [339]

Answer: On Monday, XX/XX, the XXXX you presented in our weekly review were not accurate and I’m worried that this reflected poorly on our team’s credibility. This could negatively impact senior leadership’s confidence in our team’s effectiveness at a time when headcount is already being scrutinized and potentially eliminated. Next time you present XXXX, my expectation is that everything will have been double or triple-checked in advance of the meeting so that all figures are reported accurately.

4 0
2 years ago
A holiday ornament in the shape of a hollow sphere with mass M = 1.50×10−2 kg and radius R = 5.50×10−2 m is hung from a tree lim
pickupchik [31]

Answer:

T = 0.607 seconds

Explanation:

Given:

Mass, M = 1.50 × 10⁻² kg

Radius, R = 5.50 × 10⁻² m

Now,

the time period in terms of moment of inertia is given as:

T = 2\pi\sqrt\frac{I}{mgR}    .....................1

where, T is the time period

g is the acceleration due to gravity

I is the moment of inertia

Now,

Moment of inertia, I is given as:

I = \frac{5mR^{2}}{3}

on substituting the moment of inertia in the equation 1, we get

T = 2\pi\sqrt\frac{\frac{5mR^{2}}{3}}{mgR}

or

T = 2\pi\sqrt\frac{{5R}}{3g}

on substituting the valeus, we get

T = 2\pi\sqrt\frac{{5\times5.50\times10^{-2}}}{3\times9.8}

or

T = 0.607 seconds

Hence, the time period is 0.607 seconds

5 0
3 years ago
Can someone answer this question quickly??
masya89 [10]

Answer:

Lithium and Sodium

Explanation:

Lithium and Sodium is in the same group 1A

7 0
3 years ago
A fan blade is rotating with a constant angular acceleration of 11.5 rad/s2. At what point on the blade, as measured from the ax
vichka [17]

Answer:

Alpha = ω^2 R    where R is radius of blade

g = w^2 r      where r is distance from center

ω^2 R = 11.5 ω^2 r

R / r = 11.5 / 9.8 = 1.17

Or r = .852 R

Since the angular acceleration depends on both R and ω it seems that one can only get r as it depends on R

7 0
2 years ago
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