Answer:
1) one solution
2) Infinitely many solution
3) no solution
Step-by-step explanation:
The first equation is -14-8x=-2(-3x+7)
Let us expand the right hand side to get:
-14-8x=-2*-3x+-2*7
We multiply -14-8x=6x-14
We group similar terms to get:
-8x-6x=-14+14
Combine similar terms to get:
-14x=0
Divide through by -14 to get:
x=0
2) The second equation is 3+5x=5(x+2)-7
We expand to obtain:
3+5x=5x+5*2-7
Multiply to get:
3+5x=5x+10-7
This gives us
3+5x=5x+3
5x=5x
1=1
There is infinitely many solutions
3) The third equation is: 36-7x=-7(x-5)
We expand to get:
36-7x=-7x+35
Group similar terms;
-7x+7x=35-36
0=-1
This statement is not true so there is no solution.
To solve using completing square method we proceed as follows:
x^2-10x+8=0
x^2-10x=-8
but
c=(b/2)^2
c=(10/2)^2=25
thus we can add this in our expression to get
x^2-10x+25=8+25
factorizing the LHS we get:
(x-5)(x-5)=33
(x-5)^2=33
getting the square roots of both sides we have:
x-5=+/-√33
x=5+/-√33
you find what they both divide by and then divide each one and then you keep doing that until you cant no more
Answer: Sometimes
Step-by-step explanation: Through every 2 points is a line, so it would be sometimes as a line only has a minimum of 2 points.
