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Arlecino [84]
3 years ago
7

A person walks out of a store with a pillow at the top of an overflowing shopping cart. While walking to the car, the cart's whe

el hits a large rock, causing the cart to suddenly stop. Which of the following is likely to happen as a result of Newton's first law of motion?
Physics
1 answer:
Mashutka [201]3 years ago
7 0
The pillow will continue to go forward as Newton's first law states that an object will continue in it's path unless another force acts upon it
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Answer:

if i was to have a 10kg toy car and it was moving away from you it would get smaller like you was backing up.

Explanation:

velocity means speed-

not for sure im new here so sorry if i'm wrong  

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A car's fuel economy is 30 mpg. a warning light is displayed if the remaining distance that can be driven before the car runs ou
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10 : 300 :: x : 50 

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At which point is cool air circulating beneath warm air?
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Answer:

1

Explanation:

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Read the scenario below and answer the question that follows. Jane is a psychologist. She submits a study on sleep to a prestigi
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Constant Acceleration Kinematics: Car A is traveling at 22.0 m/s and car B at 29.0 m/s. Car A is 300 m behind car B when the dri
Ainat [17]

Answer:

The taken is  t_A  = 19.0 \ s

Explanation:

Frm the question we are told that

  The speed of car A is  v_A  =  22 \ m/s

   The speed of car B is  v_B  = 29.0 \ m/s

     The distance of car B  from A is  d = 300 \ m

     The acceleration of car A is  a_A  = 2.40 \ m/s^2

For A to overtake B

    The distance traveled by car B  =  The distance traveled by car A - 300m

Now the this distance traveled by car B before it is overtaken by A is  

          d = v_B * t_A

Where t_B is the time taken by car B

Now this can also be represented as using equation of motion as

      d = v_A t_A  + \frac{1}{2}a_A t_A^2 - 300

Now substituting values

       d = 22t_A  + \frac{1}{2} (2.40)^2 t_A^2 - 300

Equating the both d

       v_B * t_A = 22t_A  + \frac{1}{2} (2.40)^2 t_A^2 - 300

substituting values

   29 * t_A = 22t_A  + \frac{1}{2} (2.40)^2 t_A^2 - 300

   7 t_A = \frac{1}{2} (2.40)^2 t_A^2 - 300

  7 t_A =1.2 t_A^2 - 300

   1.2 t_A^2 - 7 t_A - 300  = 0

Solving this using quadratic formula we have that

     t_A  = 19.0 \ s

7 0
3 years ago
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