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Andrei [34K]
3 years ago
7

Why does earth have such a diversity of plant and animal life

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
5 0
Well, originally Earth's life was extremely simple; there were only single-celled organisms. As time went on, they adapted to different environments. After that, some organisms turned into macrophages, or cells that eat things, including other cells.

Soon, some cells began to bisexually reproduce, creating a multicellular organism. These organisms were still very simple and not as complex as today's living things, but definitely more complicated than the earlier generations of life before them.

They started to adapt and evolve, as well. Another important thing to mention was Earth's atmosphere at the time. Earth didn't have it's protective little blanket of ozone that it does today, so nothing could live on the surface.

As time went on, Earth's ozone layer began to develop, preventing harmful ultraviolet light from piercing the atmosphere. Organisms slowly began to appear on land, while many others stayed in the ocean.

Evolution and adaptation occured over and over to a countless number of species, creating a huge diversity of fauna and flora. Then, most of them died. It is commonly believed today that a large asteroid struck the Earth, killing off most of its organisms.

Then, the cycle repeated. This time, however, things were different. Many organisms weren't wiped out, both on land and in water, allowing for new species to develop.

Some organisms ate other organisms. This made the prey evolve to have a higher chance of survival against the predators. Some evolved, other's didn't, causing a split. Many species did this, so even though many of them were related, they are considered different organisms all together.

This cycle happened over and over, prey vs. predator, evolving and adapting, eating and being eaten. They all grew according to each others' traits.

For example, if a predator can only see certain colors, some prey will evolve to have those colors and/or camoflauge with the ecosystem. This can be seen in the case of a cheetah and a zebra.

We can clearly see the zebra against a field, because the zebra is black and white and the field is orange, but a cheetah doesn't see the orange. It only sees some stripes (the zebra) against more stripes (the field.

Hopefully this helps. In short, everything grew according to everything else's characteristics.

Fun fact: About 99% of all species that lived on Earth are extinct. Crazy, huh?
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98.8

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CsF + XeF6 --> CsXeF7

37.8g ................. ?g

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A student combines 34 grams of one chemical and an unknown amount of another chemical in a closed system. A chemical reaction oc
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6 0
3 years ago
Nickel and carbon monoxide react to form nickel carbonyl, like this: (s)(g)(g) At a certain temperature, a chemist finds that a
horsena [70]

The question is incomplete, here is the complete question:

Nickel and carbon monoxide react to form nickel carbonyl, like this:

Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)

At a certain temperature, a chemist finds that a 2.6 L reaction vessel containing a mixture of nickel, carbon monoxide, and nickel carbonyl at equilibrium has the following composition:

Compound            Amount

     Ni                        12.7 g

   CO                        1.98 g

Ni(CO)_4                  0.597 g

Calculate the value of the equilibrium constant.

<u>Answer:</u> The value of equilibrium constant for the reaction is 2448.1

<u>Explanation:</u>

We are given:

Mass of nickel = 12.7 g

Mass of CO = 1.98 g

Mass of Ni(CO)_4 = 0.597 g

Volume of container = 2.6 L

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

\text{Equilibrium concentration of nickel}=\frac{12.7}{58.7\times 2.6}=0.083M

\text{Equilibrium concentration of CO}=\frac{1.98}{28\times 2.6}=0.0272M

\text{Equilibrium concentration of }Ni(CO)_4=\frac{0.597}{170.73\times 2.6}=0.00134M

For the given chemical reaction:

Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)

The expression of equilibrium constant for the reaction:

K_{eq}=\frac{[Ni(CO)_4]}{[CO]^4}

Concentrations of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

K_{eq}=\frac{0.00134}{(0.0272)^4}\\\\K_{eq}=2448.1

Hence, the value of equilibrium constant for the reaction is 2448.1

4 0
3 years ago
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