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Ipatiy [6.2K]
3 years ago
8

I’m taking this test and i need help

Physics
1 answer:
Nostrana [21]3 years ago
4 0
It’s the second one reactivity
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A rigid tank whose volume is unknown is divided into two parts by a partition. One side of the tank contains an ideal gas at 935
a_sh-v [17]

Answer:

2805 °C

Explanation:

If the gas in the tank behaves as ideal gas at the start and end of the process. We can use the following equation:

P=RTn/V

The key issue is identify the quantities (P,T, V, n) in the initial and final state, particularly the quantities that change.

In the initial situation the gas have an initial volume V_{i}, temperature T_{i}, and pressure P,.

And in the final situation the gas have different volume V_{f} and temeperature T_{f}, the same pressure P,, and the same number of moles n,.

We can write the gas ideal equation for each state:

P=RT_{i}n/V_{i} and P=RT_{f}n/V_{f}, as the pressure are equals in both states we can write

RT_{i}n/V_{i} = RT_{f}n/V_{f}

solving for T_{f}

T_{f} = T_{i}/V_{i} * V_{f} (*)

We know T_{i}  = 935 °C, and that the V_{f} (the complete volume of the tank) is the initial volume V_{i} plus the part initially without gas which has a volume twice the size of the initial volume (read in the statement: the other side has a volume twice the size of the part containing the gas). So the final volume  V_{f}= V_{i} + 2V_{i}=3V_{i}

Replacing in (*)

T_{f} = 935/V_{i} * 3V_{i} = 935*3= 2805

7 0
3 years ago
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