Question

The driver of a 1000 kg car traveling on a highway at 35 m-s'applies brake to avoid hitting a van in front of him, which had come to rest because of trans ahead. After the brakes are applied, a constant frictional force of 8000 N on the car car 35 m- 1,8 1000kg BOOON 52.1 State the WORK- ENERGY THEOREM in words 22 Using ENERGY PRINCIPLES, determine the minimum distance requi for the brakes of the car to be applied to avoid a collision with the van?
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Answer 1

Answer:

Explanation:

kinetic energy will be converted to work of friction

½mv² = Fd

d = mv²/2F = 1000(35²) / (2(8000)) = 76.5625 ≈ 77 m

will be the minimum stopping distance d