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kow [346]
3 years ago
7

Is the atom indicated with an arrow nucleophilic, electrophilic, acidic, more than one of these choices, or none of these choice

s? (For purposes of this question, acidic is defined as pKa ≤ 25.)Select all that apply.a) nucleophilicb) electrophilicc) acidicd) none of the above
Chemistry
1 answer:
CaHeK987 [17]3 years ago
4 0

Answer:

c) acidic

Explanation:

pKa is a value which describes the acidity of a solution. The solution is pKa ≤ 25 which means that the solution is more acidic. The lower value of pKa tells us that the solution is more acidic but when the pKa value of solution increases the acidity of the solution is also decreases. Due to lower value of pKa, the acid in the solution is fully dissociates in water.-5 to 50 is the range of the value of pKa for different solutions.

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How to solve for K when given your anode and cathode equations and voltage
Aleks04 [339]

Answer:

See Explanation

Explanation:

In thermodynamics theory the Free Energy (ΔG) of a chemical system is described by the expression ΔG = ΔG° + RTlnQ. When chemical system is at equilibrium ΔG = 0. Substituting into the system expression gives ...

0 = ΔG° + RTlnKc, which rearranges to ΔG° = - RTlnKc.  ΔG° in electrochemical terms gives ΔG° = - nFE°, where n = charge transfer, F = Faraday Constant = 96,500 amp·sec and E° = Standard Reduction Potential of the electrochemical system of interest.

Substituting into the ΔG° expression above gives

-nFE°(cell) = -RTlnKc => E°(cell) = (-RT/-nF)lnKc = (2.303·R·T/n·F)logKc

=> E°(cell) = (0.0592/n)logKc = E°(Reduction) - E°(Oxidation)

Application example:

Calculate the Kc value for a Zinc/Copper electrochemical cell.

Zn° => Zn⁺² + 2e⁻  ;    E°(Zn) = -0.76 volt  

Cu° => Cu⁺² + 2e⁻ ;    E°(Cu) =  0.34 volt

By natural process, charge transfer occurs from the more negative reduction potential to the more positive reduction potential.

That is,

           Zn° => Zn⁺² + 2e⁻ (Oxidation Rxn)

Cu⁺² + 2e⁻ => Cu°             (Reduction Rxn)

E°(Zn/Cu) = (0.0592/n)logKc

= (0.0592/2)logKc = E°(Cu) - E°(Zn) = 0.34v - (-0.76v) = 1.10v

=> logKc = 2(1.10)/0.0592 = 37.2

=> Kc = 10³⁷°² = 1.45 x 10³⁷

3 0
3 years ago
PLEASE HELP!! How could using either more or less of a chemical in a scientific experiment cause a change in results?
charle [14.2K]
The chemical could have more or less of a reaction to the other chemicals in the experiment
4 0
3 years ago
HELP.
Kamila [148]

Answer:

The mass of tin is 164 grams

Explanation:

Step 1: Data given

Specific heat heat of tin = 0.222 J/g°C

The initial temeprature of tin = 80.0 °C

Mass of water = 100.0 grams

The specific heat of water = 4.184 J/g°C

Initial temperature = 30.0 °C

The final temperature = 34.0 °C

Step 2: Calculate the mass of tin

Heat lost = heat gained

Qlost = -Qgained

Qtin = -Qwater

Q = m*c*ΔT

m(tin)*c(tin)*ΔT(tin) = -m(water)*c(water)*ΔT(water)

⇒with m(tin) = the mass of tin = TO BE DETERMINED

⇒with c(tin) = the specific heat of tin = 0.222J/g°C

⇒with ΔT(tin) = the change of temperature of tin = T2 - T1 = 34.0°C - 80.0°C = -46.0°C

⇒with m(water) = the mass of water = 100.0 grams

⇒with c(water) = the specific heat of water = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = 34.0° C - 30.0 °C = 4.0 °C

m(tin) * 0.222 J/g°C * -46.0 °C = -100.0g* 4.184 J/g°C * 4.0 °C

m(tin) =  163.9 grams ≈ 164 grams

The mass of tin is 164 grams

4 0
3 years ago
Sensitivity analysis is concerned with how certain changes affect
Ilia_Sergeevich [38]
The answer here is letter C. The optimal solution. The optimal solution is the one that affects how certain things changes with sensitivity analysis. The optimal solution is a feasibility solution where the objective function of it is to reach the minimum and maximum value.
8 0
3 years ago
Calculate the energy per photon (in J) associated with a frequency of 1260 kHz. Submit answer in scientific notation using the f
aniked [119]

Taking into account the definition of photon and energy of a photon, the energy per photon is 8.3538×10⁻³⁸ J.

<h3>Energy of a photon</h3>

Electromagnetic radiation carries energy, which can be absorbed or emitted. To explain the processes of emission and absortion, Plank and Einstein proposed that the energy of radiation is composed of indivisible units (quanta). In each elemental process only a quantum of light can be emitted or absorbed. Each of these quanta was called a "photon".

The exchanges of energy between matter and radiation take place not continuously, but by discrete and indivisible quantities or quanta of energy. The quantum of energy is proportional to the frequency of radiation.

The relationship between the amount of energy (E) transported by the photon and its frequency (f) is determined by the following expression:

E=h×f

where:

  • E is the energy of a photon.
  • h is the Planck's constant h.
  • f is the frequency of electromagnetic radiation.

<h3>Energy per photon</h3>

In this case, you know:

  • h=  6.63*10⁻³⁴ Js
  • f= 1260 kHz= 1,260,000 Hz= 1.26×10⁶ Hz (being 1 kHz=1000 Hz)

Replacing in the definition of energy of a photon:

E= 1.26×10⁶ Hz× 6.63×10⁻³⁴ Js

<u><em>E= 8.3538×10⁻³⁸ J</em></u>

Finally, the energy per photon is 8.3538×10⁻³⁸ J.

Learn more about energy of a photon:

brainly.com/question/8924116

brainly.com/question/6945706

brainly.com/question/8000078

#SPJ1

6 0
2 years ago
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