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3 years ago

Which of the following is a unit for mass in the International System of Units?

1 answer:

6 0

Remember this King Henry Died Unfortunatly Drinking Chocolate Milk look this up online. The answer is Kilo. #TeamAlvaxic

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1. What allowed fusion reactions to take place in the early universe?

olasank [31]

Answer:

Nuclear fusion in stars converts hydrogen into helium in all stars

8 0

2 years ago

Read 2 more answers

If 15g of iron reacts with 8.5g of oxygen, how many grams of iron oxide will be produced

just olya [345]

Answer:

23.5g of FeO

Explanation:

Hello,

The question above is asking us to find the mass of iron oxide produced from 15g of Fe and 8.5g of O. Well, to solve this question, we'll require the equation of reaction.

2Fe + O₂ → 2FeO

From the equation of reaction, 2 moles of Fe plus 1 mole of oxygen will produce 2 moles of FeO

Molar mass of Fe = 56g/mol

Molar mass of FeO = 72g/mol

Molar mass of O = 16 × 2 = 32g/mol

Number of moles = mass / molar mass

Mass = number of moles × molar mass

Mass of Fe = 2 × 56 = 112g

Mass of O = 32g

Mass of FeO = 2 × 72 = 144g

From the equation of reaction, (112 + 32)g (Fe + O2) reacts to produce 144g of FeO

114g of reacts produce 114g of FeO

15g of Fe + 8.5g of O2 = ?

(15 + 8.5)g (Fe + O2) = x

X = (23.5 × 114) / 114

x = 23.5g

Therefore, 15g of Fe and 8.5g of O2 will react to produce 23.5g of FeO

6 0

3 years ago

½O2(g) + H2(g) ⇌ H2O(g)

ira [324]

Answer:

-241.826 kJ·mol⁻¹; -146.9 J·K⁻¹mol⁻¹; 664.6 J·K⁻¹mol⁻¹; spontaneous

Explanation:

½O₂(g) + H₂(g) ⟶ H₂O(g)

ΔHf°/kJ·mol⁻¹: 0 0 -241.826

S°/J·K⁻¹mol⁻¹: 205.0 130.6 188.7

1. ΔᵣH

ΔᵣH = products -reactants = -241.826 -(0 + 0) = -241.826 kJ·mol⁻¹

2. ΔᵣS

ΔᵣS = products - reactants = 188.7 - (205.0 + 130.6) = 188.7 - 335.6 = -146.9 J·K⁻¹mol⁻¹

3. ΔS(univ)

$\begin{array}{rcl}\Delta S_{\text{univ}} &=& \Delta S_{\text{sys}} +\Delta S_{\text{surr}}\\\\ &=& \Delta S_{\text{sys}} -\dfrac{\Delta H_{\text{sys}}}{T}\\\\& = & -146.9 - \dfrac{-241826}{298}\\\\& = & -146.9 + 811.5\\& = & \mathbf{664.6 \,\, J\cdot K^{-1}mol^{-1}}\\\end{array}$

4. Spontaneity

$\begin{array}{rcl}\Delta G &=& \Delta H - T\Delta S\\& = & -241.826 - 298 \times (-0.1469)\\& = & -241.826 + 43.776\\& = & \textbf{-198.050 kJ}\cdot\textbf{mol}^{\mathbf{-1}}\\\end{array}$

ΔG is negative, so the reaction is spontaneous.

4 0

3 years ago

How does a conjugate acid differ from its conjugate base?

inna [77]

The conjugate acid is differ from its conjugate base as, conjugate acid is formed by strong base whereas conjugate base is formed by strong acid.

conjugate base is differ from conjugate acids by the presence of the proton. The conjugate acid is formed when proton is added to the bases whereas conjugate bases is formed when proton is released by the acids.

Example of corrugate acids are given below.

$NH_{3}$ → $NH_{2} ^{-} +H^{+}$