Answer:
The pressure inside the container would increase with each additional pump.
Explanation:
- From the general gas law of ideal gases:
<em>PV = nRT,</em>
where, P is the pressure of the gas.
V is the volume of the gas.
n is the no. of moles of the gas.
R is the general gas constant.
T is the temperature of the gas.
- As clear from the gas law; the pressure of the gas is directly proportional to the no. of moles of the gas.
<em>P α n.</em>
- As gas particles are pumped into a rigid steel container, the no. of moles of the gas will increase.
So, the pressure of the gas will increase.
<em>Thus, the right choice is: The pressure inside the container would increase with each additional pump.</em>
Answer:
It increases when a catalyst is added.
Explanation:
The following factors control reaction rates:
1. Nature of reactants
2. Concentration of the reactants or pressure of gaseous
3. Temperature
4. Presence of catalyst
5. Sunlight
The addition of a foreign body to a reaction may influence the speed of the reaction. If a foreign body increases the rate of reaction, it is a called a positive catalyst or simply a catalyst. A negative catalyst is called an inhibitor.
A catalyst is a substance that is introduced into a chemical reaction to change the rate of the reaction without itself being affected at the end of the reaction.
Catalysts helps to reduce reaction time of many slow reactions. Most catalysts are specific in their actions and works on certain reactions or substrates.
Temperature change has a considerable effect on reaction rates since temperature is directly proportional to the average kinetic energy of reacting particles. Generally, reaction rate varies as temperature directly.
Answer:
Potassium citrate (also known as tripotassium citrate) is a potassium salt of citric acid with the molecular formula K3C6H5O7.
Chemical formula: K3C6H5O7
Density: 1.98 g/cm3
Melting point: 180 °C (356 °F; 453 K)
Boiling point: 230 °C (446 °F; 503 K)
Explanation:
I would assume it would be impossible or unlikely
Answer:
w = -531 kJ
1. Work was done by the system.
Explanation:
Step 1: Given data
- Heat gained by the system (q): 687 kJ (By convention, when the system absorbs heat, q > 0).
- Change in the internal energy of the system (ΔU°): 156 kJ
Step 2: Calculate the work done (w)
We will use the following expression.
ΔU° = q + w
w = ΔU° - q
w = 156 kJ - 687 kJ
w = -531 kJ
By convention, when w < 0, work is done by the system on the surroundings.
