Answer:
Hi,
The correct answer option is; D. Most of the current will flow through one part of the circuit.
Explanation:
A short circuit is a low resistance path in an electric connection between two conductors supplying current in a circuit.
It happens when excess amounts of current flow in the power source through a 'short path'.
Short circuits occur at very high temperatures which is of course caused by the heat produced during dissipation.
An example of application of short circuit is arc welding, where heating is achieved through short circuit.
Answer:
d. conduction
Explanation:
Conduction involves the transfer of electric charge or thermal energy due to the movement of particles. When the conduction relates to electric charge, it is known as electrical conduction while when it relates to thermal energy, it is known as heat conduction.
In the process of heat conduction, thermal energy is usually transferred from fast moving particles to slow moving particles during the collision of these particles. Also, thermal energy is typically transferred between objects that has different degrees of temperature and materials (particles) that are directly in contact with each other but differ in their ability to accept or give up electrons.
Any material or object that allow the conduction (transfer) of electric charge or thermal energy is generally referred to as a conductor. Conductors include metal, steel, aluminum, copper, frying pan, pot, spoon etc.
In conclusion, conduction typically involves the transfer of heat energy by direct contact between two or more conductors such as a pot and electric cooker.
Answer:
Startinfg speed is 13.82 m/s
Explanation:
Use equation for realtion between start and final speed :
Vf=Vs+a*t
Vf-final speed
Vs-start speed
Vf=24.44m/s
a=1.77m/s²(acceleration)
t=6.00s(Time)
Vf=Vs+a*t
Vs=a*t-Vf
Vs=1.77m/s²*6s-24.44m/s
Vs=-13.82m/s
Answer:
a. a=33.34ms⁻², V=164.4m/s
Explanation:
Since the dragster started with zero velocity, de determine the acceleration using of the equations of motion.
Below are the data given
Distance, s=404.5m,
time taken,t=4.922secs
Using the equation
S=ut+1/2at²
where u is the initial velocity and u=0
Making the acceleration the subject of the formula, we arrive at
a=2s/t²
a=(2*404.5)/4.922²
a=33.34ms⁻².
To determine the velocity, we use
V=u+at
V=0+33.34ms⁻² *4.922sec
V=164.4m/s
D is the correct answer!!