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3 years ago

Which of the following would NOT be considered vigorous aerobic exercise?

Physics

2 answers:

NikAS [45]3 years ago

7 0

Answer:

Explanation:

walking is not particularly vigorous

zhannawk [14.2K]3 years ago

5 0

Answer:

Option A

Explanation:

As while walking we doesn't speed so no speed(vigorous) respiration..

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A cue ball, moving with 9.0 N·s of momentum strikes the nine-ball at rest. The nine-ball moves off with 2.0 N·s in the original

lisov135 [29]

Answer:

P = 7.28 N.s

Explanation:

given,

initial momentum of cue ball in x- direction,P₁ = 9 N.s

momentum of nine ball in x- direction, P₂ = 2 N.s

momentum in perpendicular direction i.e. y - direction,P'₂ = 2 N.s

momentum of the cue after collision = ?

using conservation of momentum

in x- direction

P₁ + p = x + P₂

p is the initial momentum of the nine balls which is equal to zero.

9 + 0 = x + 2

x = 7 N.s

momentum in x-direction.

equating along y-direction

P'₁ + p = y + P'₂

0 + 0 = y + 2

y = -2 N.s

the momentum of the cue ball after collision is equal to resultant of the momentum .

$P = \sqrt{x^2+y^2}$

$P = \sqrt{7^2+(-2)^2}$

P = 7.28 N.s

the momentum of the cue ball after collision is equal to P = 7.28 N.s

7 0

3 years ago

A train, traveling at a constant speed of 22.0 m/s, comes to an incline with a constant slope. While going up the incline, the t

Charra [1.4K]

Answer:

123.30 m

Explanation:

Given

Speed, u = 22 m/s

acceleration, a = 1.40 m/s²

time, t = 7.30 s

From equation of motion,

v = u + at

where,

v is the final velocity

u is the initial velocity

a is the acceleration

t is time

V = at + U

using equation v - u = at to get line equation for the graph of the motion of the train on the incline plane

$V_{x} = mt + V_{o}$ where m is the slope

Comparing equation (1) and (2)

$V = V_{x}$

a = m

$U = V_{o}$

Since the train slows down with a constant acceleration of magnitude 1.40 m/s² when going up the incline plane. This implies the train is decelerating. Therefore, the train is experiencing negative acceleration.

a = - 1.40 m/s²

Sunstituting a = - 1.40 m/s² and u = 22 m/s

$V_{x} = -1.40t + 22$

$V_{x} = -1.40(7.30) + 22$

$V_{x} = -10.22 + 22$

$V_{x} = 11. 78 m/s$

The speed of the train at 7.30 s is 11.78 m/s.

The distance traveled after 7.30 sec on the incline is the area cover on the incline under the specific interval.

Area of triangle + Area of rectangle

$[\frac{1}{2} * (22 - 11.78) * (7.30)] + [(11.78 - 0) * (7.30)]$

= 37.303 + 85.994

= 123. 297 m

≈ 123. 30 m

4 0

3 years ago

Read 2 more answers

calculate the force required to take away a flat corcular plate of radius 0.01m from the surface of water. the surface tention o

leonid [27]

Answer:

$Force = 0.0047175\ N$

Explanation:

Given

$T = 0.075N/m$ --- Surface Tension

$r = 0.01m$ --- Radius

Required

Determine the required force

First, we calculate the circumference (C) of the circular plate

$C= 2\pi r$

$C= 2 * \frac{22}{7} * 0.01m$

$C= \frac{2 * 22 * 0.01}{7}m$

$C= \frac{0.44}{7}m$

$C= 0.0629 m$

The applied force is then calculated using;

$Force = C * T$

$Force = 0.0629m * 0.075N/m$

$Force = 0.0047175\ N$

8 0

3 years ago

A researcher finds that blood alcohol levels cause Progressive damage the liver all of mice and his study were fed the same amou

Juli2301 [7.4K]

Answer:hmm

Explanation:

4 0

3 years ago

A ball rolling along a floor doesn't continue rolling indefinitely. is it because it is seeking a place of rest or because some

Ivan

It is because gravity is pushing down on the ball

7 0

3 years ago