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devlian [24]
3 years ago
5

Which of the following would NOT be considered vigorous aerobic exercise?

Physics
2 answers:
NikAS [45]3 years ago
7 0

Answer:

A

Explanation:

walking is not particularly vigorous

zhannawk [14.2K]3 years ago
5 0

Answer:

Option A

Explanation:

As while walking we doesn't speed so no speed(vigorous) respiration..

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A major strike-slip earthquake on the San Andreas fault in California will cause a catastrophic tsunami affecting residents of S
ZanzabumX [31]

Answer:

a) true

Explanation:

  • The san andres is a transform fault that forms boundary between the Pacific and the North Atlantic plate and this slip strike is characterized by the latex motion the fault runs in the length of the California state.
  • This plate is widely estimated for the high magnitude of earthquakes and varies from 7.7 to 8.3 magnitude. They are capable of producing a deadly tsunami that can devastate the pacific northwest.
6 0
3 years ago
Which characteristic surface of the moon contains the same rock as the ocean floor
Ratling [72]
The answer is Maria or Lunar mare because they are both made of basalt. Hope this helps.
3 0
3 years ago
Energy ___________.
AVprozaik [17]

Answer:

BRAINLIEST PLSSSSSSSSSSSSSSSSSSSSSSSS

Thermodynamics

Explanation:

Thermodynamics is the study of energy. First Law of Thermodynamics: Energy can be changed from one form to another, but it cannot be created or destroyed. The total amount of energy and matter in the Universe remains constant, merely changing from one form to another.

7 0
3 years ago
Read 2 more answers
A current of 16.0 mA is maintained in a single circular loop of 1.90 m circumference. A magnetic field of 0.790 T is directed pa
pav-90 [236]

Answer

given,

current (I) = 16 mA

circumference of the circular loop (S)= 1.90 m

Magnetic field (B)= 0.790 T

S = 2 π r

1.9 = 2 π r

r = 0.3024 m

a) magnetic moment of loop

    M= I A

    M=16 \times 10^{-3} \times \pi \times r^2

   M=16 \times 10^{-3} \times \pi \times 0.3024^2

   M=4.59 \times 10^{-3}\ A m^2

b)  torque exerted in the loop

 \tau = M\ B

 \tau = 4.59 \times 10^{-3}\times 0.79

 \tau = 3.63 \times 10^{-3} N.m

8 0
3 years ago
Joe drove at the speed of 45 miles per hour for a certain distance. He then drove at the speed of 55 miles per hour for the same
Snowcat [4.5K]

Answer:

v_{avg} = 49.5 mph

Explanation:

Let the distance moved by Joe is "d"

so the time taken by him to drove it by speed 45 mph is given as

t_1 = \frac{d}{v_1}

t_1 = \frac{d}{45}

now the same distance is traveled by him with speed 55 mph

so the time taken by him

t_2 = \frac{d}{55}

so total time taken by him for complete distance 2d

t = t_1 + t_2

t = \frac{d}{45} + \frac{d}{55}

t = 0.0404 d

now the average speed is given as

v_{avg} = \frac{2d}{t}

v_{avg} = \frac{2d}{0.0404d}

v_{avg} = 49.5 mph

5 0
3 years ago
Read 2 more answers
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