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MrRissso [65]
3 years ago
6

The person in the middle weighs 500 n, and the tension on the rope is 400 n. what is the weight of the scaffolding?

Physics
1 answer:
Alina [70]3 years ago
7 0

Typically a scaffolding has two ropes to support it. One on the left most side while the other one is on the right most side. Based on equilibrium rule, the summation of forces must be 0. The downward force is the weight of person and scaffolding, while the upward force are the tensions on the two ropes, hence:

Weight person + Weight scaffolding = 2 * Tension

500 N + Weight scaffolding = 2 * 400 N

Weight scaffolding = 300 N

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Answer:

- After throwing the snow, velocity of the thrower is 2.33 m/s

- the velocity of the receiver is 0.026 m/s

Explanation:

Given the data in the question;

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(69.5 kg + 0.0475 kg) × 2.35 m/s = 163.4366 kg.m/s

Now, When he throws it at 31.5 m/s, these constitutes a momentum of;

(0.0475 kg )(31.5 m/s) = 1.49625 kg.m/s

hence his momentum now is: 163.4366 - 1.49625 = 161.94035 kg.m/s

To get his velocity, we say;

161.94035 = mv

{ he lost weight of the snow ball so, m = 69.5 kg )

161.94035 = 69.5 × v

v = 161.94035 / 69.5

v = 2.33 m/s

Therefore, After throwing the snow, velocity of the thrower is 2.33 m/s

Next is the Receiver;

the receiver will gain momentum of 1.49625 kg.m/s

he has no momentum initially and after he catches the snow ball;

1.49625 kg.m/s = mv

1.49625 kg.m/s = ( 57.5 kg +  0.0475 kg ) × v

1.49625 kg.m/s = 57.5475 kg × v

v = ( 1.49625 kg.m/s ) / 57.5475 kg

v = 0.026 m/s

Therefore, the velocity of the receiver is 0.026 m/s

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