Answer: The second force applied to the doorknob
Explanation:
The formulae for torque is simple the product of the applied force and the perpendicular distance.
The greater the perpendicular force, the greater the torque assuming a constant value of force.
Applying the force at the doorknob gives for a greater distance between the force and the turning point compared to applying the force at the midpoint of the door ( which is at a shorter distance)
Answer:
v = 0.653 m/s
Explanation:
given,
mass of auto mobile = 941 Kg
spring constant = 2.37 x 10⁶ N/m
compressed by the car = 1.61 cm = 0.0161 m
we have,
v = 0.653 m/s
hence, velocity of car before impact is equal to 0.653 m/s
Answer:
<h2> 27m/s</h2>
Explanation:
Given data
initital velocity u=15m/s
deceleration a=3m/s^2
time t= 4 seconds
final velocity v= ?
Applying the expression
v=u+at------1
substituting our data into the expression we have
v=15+3*4
v=15+12
v=27m/s
The velocity after 4 seconds is 27m/s
<h2>Answer </h2>
C. 40 m/s
<h2>Explanation </h2>
To solve this, we are using the kinematic equation for final velocity:
where
is the final velocity
is the initial velocity
is the acceleration
is the time
We know from our a problem that a motorcycle moving at 20 m/s accelerates uniformly 2 m/s^2 for 10 seconds, so , , and .
Now we can replace the values
We can conclude that the velocity of the motorcycle will be 40 m/s after 10 seconds.
Solution :
A vector is defined as an element that has magnitude of some measure and direction.
It is given there is vector 'd' which has magnitude 2.6 m and its direction is towards north.
a). -d
The magnitude of the vector '-d' is 2.6 m and its direction is reversed, i.e. its direction is towards south.
b). d/2.0
The magnitude of the vector 'd/2.0' is 1.3 m and its direction is towards north.
c). - 2.5d
The magnitude of the vector increases by 2.5 times i.e. 2.5 x 2.6 = 6.5 m and the direction is towards south.
d). 5.0d
The magnitude of the vector increases by 5 times i.e. 5 x 2.6 = 13 m and the direction is towards north.