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Marrrta [24]
3 years ago
11

The place kicker on a football team kicks a ball from ground level with an initial speed of 5.80 m/s at an angle of 17.0° above

the horizontal. How long is the ball in the air before it lands on the ground again
Physics
1 answer:
Likurg_2 [28]3 years ago
8 0

Answer:

0.34 s

Explanation:

Given that,

Initial speed of a ball, u = 5.8 m/s

It is kicked at an angle of 17.0° above the horizontal.

The vertical component of velocity will be,

u_y=u\sin\theta\\\\=5.8\times \sin 17\\\\=1.69\ m/s

Let it takes t time in the air before it lands on the ground again. It can calculated as :

t=\dfrac{2u_y}{g}\\\\t=\dfrac{2\times 1.69}{9.8}\\\\t=0.34\ s

So, it will take 0.34 seconds.

You might be interested in
. (a) How high a hill can a car coast up (engine disengaged) if work done by friction is negligible and its initial speed is 110
7nadin3 [17]

Answer:

(a) the high of a hill that car can coast up (engine disengaged) if work done by friction is negligible and its initial speed is 110 km/h is 47.6 m

(b) thermal energy was generated by friction is 1.88 x 10^{5} J

(C) the average force of friction if the hill has a slope 2.5º above the horizontal is 373 N

Explanation:

given information:

m = 750 kg

initial velocity, v_{0} = 110 km/h = 110 x 1000/3600 = 30.6 m/s\frac{30.6^{2} }{2x9.8}

initial height, h_{0} = 22 m

slope, θ = 2.5°

(a) How high a hill can a car coast up (engine disengaged) if work done by friction is negligible and its initial speed is 110 km/h?

according to conservation-energy

EP = EK

mgh = \frac{1}{2} mv_{0} ^{2}

gh = \frac{1}{2} v_{0} ^{2}

h = \frac{v_{0} ^{2} }{2g}

  = 47.6 m

(b) If, in actuality, a 750-kg car with an initial speed of 110 km/h is observed to coast up a hill to a height 22.0 m above its starting point, how much thermal energy was generated by friction?

thermal energy = mgΔh

                         = mg (h - h_{0})

                         = 750 x 9.8 x (47.6 - 22)

                         = 188160 Joule

                         = 1.88 x 10^{5} J

(c) What is the average force of friction if the hill has a slope 2.5º above the horizontal?

f d  = mgΔh

f = mgΔh / d,

where h = d sin θ, d = h/sinθ

therefore

f = (mgΔh) / (h/sinθ)

 = 1.88 x 10^{5}/(22/sin 2.5°)

 = 373 N

8 0
3 years ago
A 350-g mass is attached to a spring whose spring constant is 64 N/m. Its maximum acceleration is 5.3 m/s2. What is the frequenc
max2010maxim [7]

The frequency of oscillation is 2.153 Hz

What is the frequency of spring?

Spring Frequency is the natural frequency of spring with a weight at the lower end. Spring is fixed from the upper end and the lower end is free.

For the mass-spring system in this problem,

The Frequency of spring is calculated with the equation:

f = \frac{1}{2\pi } \sqrt{\frac{k}{m} }

Where,

f = frequency of spring

k = spring constant = 64 N/m

m = mass attached to spring = 350g = 0.350 kg

a = maximum acceleration = 5.3 m/s^2

Substituting the values in the equation,

f = \frac{1}{2\pi } \sqrt{\frac{64}{0.350} }

f = \frac{1}{2\pi } ( 13.522)

f = 2.1535 Hz

Hence,

The frequency of oscillation is 2.153 Hz

Learn more about frequency here:

<u>brainly.com/question/13978015</u>

#SPJ4

6 0
2 years ago
what is the acceleration of an object if the object has an initial speed of 230 m/s and speeds up to 650 m/s. The time it takes
adell [148]

Answer:

explain this

Explanation:

7 0
3 years ago
5. Two charged particles are separated by a distance of 12 meters. The Coulomb force between them is 20 N. What will the Coulomb
Leni [432]

Answer:

A) 80 N

Explanation:

The closer the particles get, the stronger the Coulomb force, which elongates choices C and D. The Coulomb force is inversely proportional to the distance squared. If the distance is cut in half, the force is multiplied by the reciprocal of (1/2)^2, which is 4. Multiplying it out, 20 times 4 is 80 N.

8 0
3 years ago
Which of the following is/are true? Electromagnetic waves are created by accelerating charges. Electromagnetic waves are transve
Vikki [24]

Answer:

All of the above are true.

Explanation:

(a). true  

whenever  charge particle  move back and froth from its mean position then it will produce oscillating electric and magnetic fields, . so an em wave can be obtain by accelerating charge

(b). true

the electric field and the magnetic field have vibrations in the perpendicular direction along  the motion of the wave  so electromagnetic wave is a transverse wave. therefore, the EM wave is a Transverse wave

(c) true .

The Electromagnetic wave consists of the two mutually perpendicular electric and magnetic fields  and also both fields are  perpendicular to the direction of propagation of the wave.

(d) true .

An electromagnetic wave  carry  energy through  vacuum with a speed   of 3 \times 10^8 m/s  

   so , all of the above are true.

4 0
3 years ago
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