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Marrrta [24]
3 years ago
11

The place kicker on a football team kicks a ball from ground level with an initial speed of 5.80 m/s at an angle of 17.0° above

the horizontal. How long is the ball in the air before it lands on the ground again
Physics
1 answer:
Likurg_2 [28]3 years ago
8 0

Answer:

0.34 s

Explanation:

Given that,

Initial speed of a ball, u = 5.8 m/s

It is kicked at an angle of 17.0° above the horizontal.

The vertical component of velocity will be,

u_y=u\sin\theta\\\\=5.8\times \sin 17\\\\=1.69\ m/s

Let it takes t time in the air before it lands on the ground again. It can calculated as :

t=\dfrac{2u_y}{g}\\\\t=\dfrac{2\times 1.69}{9.8}\\\\t=0.34\ s

So, it will take 0.34 seconds.

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Answer:

See below

Explanation:

Normal force = m g cos 53 = 8 kg * 9.8 m/s^2 * cos 53 = 47.1823 N

  no work is done by this force

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Force Downplane = mg sin 53 = 62.61  N

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Net Force downplane =   force downplane - force friction = 55.06 N

net Work = force * distance = 55.06 N * 2 M = 110.12 j

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Suppose that, while lying on a beach near the equator of a far-off planet watching the sun set over a calm ocean, you start a st
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