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zaharov [31]
3 years ago
8

Which statement is true if the Delta.Hrxn of a reaction is positive? The reaction is endothermic. The reaction is exothermic. Th

ere is more reactant than product. There is more product than reactant.
Chemistry
2 answers:
Lyrx [107]3 years ago
5 0

Answer:

the answer is a

Explanation:

KatRina [158]3 years ago
3 0

Answer:

The reaction is endothermic.

Explanation:

Heat is absorbed in endothermic reactions. An endothermic process is any process which requires or absorbs energy from its surroundings, usually in the form of heat. It may be a chemical process, such as dissolving ammonium nitrate in water, or a physical process, such as the melting of ice cubes (wikipedia)

Standard Enthalpy of Reaction (ΔHrxn) is the amount of heat absorbed (+ΔH value) or released (-ΔH value) that results from a chemical reaction.

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The formula you need is: heat= specific heat x mass x ΔT

specific heat= 0.46 j/g-C
mass= 100.0 grams
ΔT= 40.2 - 15.0= 25.2C

heat= (0.46) x (100.0) x (25.2)=  1159.2 joules or 1200 joules (rounded off)

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3 years ago
Which statements are true? The oxidation number for Cu(s) is +2. An oxidizing agent gains electrons. Na+ is formed from the redu
just olya [345]

<u>Answer:</u> The correct statements are:

An oxidizing agent gains electrons and Zn^{2+} is formed from the oxidation of Zn(s).

<u>Explanation:</u>

For the given options:

  • <u>Statement 1</u>: The oxidation number for Cu(s) is +2

Copper is the 29th element of the periodic table having electronic configuration of [Ar]3d^{10}4s^1

This element can show +1 or +2 oxidation states. Thus, this statement is false.

  • <u>Statement 2:</u> An oxidizing agent gains electrons.

Oxidizing agents are defined as the agents which oxidize other substance and itself gets reduced. These agents undergoes reduction reactions and reduction reaction is the reaction in which an atom gains electrons.

Thus, this statement is True.

  • <u>Statement 3:</u>  Na^+ is formed from the reduction of Na(s)

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

X\rightarrow X^{n+}+ne^-

Sodium is the 11th element and it will loose electrons to form sodium ion.

Na\rightarrow Na^++e^-

Hence, this statement is false.

  • <u>Statement 4:</u> The oxidation number for Hg(l) is 0.

Mercury is the 80th element of the periodic tale having electronic configuration of [Xe]4f^{14}5d^{10}6s^2

This element can show +1 or +2 oxidation states. Thus, this statement is false.

  • <u>Statement 5:</u> A reducing agent gains electrons.

Reducing agents are defined as the agents which reduces the other substance and itself gets oxidized. These agents undergoes oxidation reactions and oxidation reaction is defined as the reaction in which an atom looses its electrons.

Thus, this statement is false.

  • <u>Statement 6:</u>  Zn^{2+} is formed from the oxidation of Zn(s)

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

X\rightarrow X^{n+}+ne^-

Zinc is the 30th element and it will loose electrons to form zinc ion.

Zn\rightarrow Zn^{2+}+2e^-

Thus, this statement is True.

Hence, the correct statements are:

An oxidizing agent gains electrons and Zn^{2+} is formed from the oxidation of Zn(s).

4 0
3 years ago
Read 2 more answers
A solution of HNO3HNO3 is standardized by reaction with pure sodium carbonate. 2H++Na2CO3⟶2Na++H2O+CO2 2H++Na2CO3⟶2Na++H2O+CO2 A
Gemiola [76]

Answer:

(0,653±0,002) M of HNO₃

Explanation:

The reaction of standarization of HNO₃ with Na₂CO₃ is:

2 HNO₃ + Na₂CO₃ ⇒ 2 Na⁺ + H₂O + CO₂ + 2NO₃⁻

To obtain molarity of HNO₃ we need to know both moles and volume of this acid. The volume is (27,71±0,05) mL and to calculate the moles it is necessary to obtain the Na₂CO₃ moles and then convert these to HNO₃ moles, thus:

0,9585 g of Na₂CO₃ × ( 1 mole / 105,988 g) =

9,043×10⁻³ mol Na₂CO₃ × ( 2 moles of HNO₃ / 1 mole of Na₂CO₃) = 1,809×10⁻² moles of HNO₃

Molarity is moles divide liters, thus, molarity of HNO₃ is:

1,809×10⁻² moles / 0,02771 L = 0,6527 M of HNO₃

The absolute uncertainty of multiplication is the sum of relative uncertainty, thus:

ΔM = 0,6527M× (0,0007/0,9585 + 0,001/105,988 + 0,05/27,71) =

0,6527 M× 2,54×10⁻³ = 1,7×10⁻³ M

Thus, molarity of HNO₃ solution and its absolute uncertainty is:

(0,653±0,002) M of HNO₃

I hope it helps!

5 0
4 years ago
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