Answer:
Explanation:
Example #1: How many moles of oxygen will occupy a volume of 2.50 L at STP? Standard ... What is the volume of gas at 2.00 atm and 200.0 K if its original volume was ... P2 = 2.00 atm 2.000tm) 273k. T=273k. 200.0k. Tz= 200.0k. V, = 200.0L ... A gas has a pressure of 0.370 atm at 50.0°C. What is the pressure at standard.
A) Head to tail joining of monomers. :) (confirmed correct answer, I took the test)
F. because electronegativity generally increases as you move from left to right across a periodic table, and F is farther right than O
Answer:
0.665 moles of CO₂
Explanation:
The balance chemical equation for the combustion of Ethane is as follow:
2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O
Step 1: <u>Calculate moles of C₂H₆ as;</u>
Moles = Mass / M.Mass
Putting values,
Moles = 10.0 g / 30.07 g/mol
Moles = 0.3325 moles
Step 2: <u>Calculate Moles of CO₂ as;</u>
According to balance chemical equation,
2 moles of C₂H₆ produced = 4 moles of CO₂
So,
0.3325 moles of C₂H₆ will produce = X moles of CO₂
Solving for X,
X = 0.3325 mol × 4 mol ÷ 2 mol
X = 0.665 moles of CO₂
