Answer:
D
Explanation:
heat is an energy that transfers from a hot body to cold body
Answer:
![27.164 lb/in^2](https://tex.z-dn.net/?f=27.164%20lb%2Fin%5E2)
Explanation:
We are given that
Gauge pressure at 3.4 degree Celsius,P=![24lb/in^2](https://tex.z-dn.net/?f=24lb%2Fin%5E2)
We have to find the gauge pressure in tire when the temperature rises to 26 degree Celsius.
Atmospheric pressure=![14.7lb/in^2](https://tex.z-dn.net/?f=14.7lb%2Fin%5E2)
![P_1=P+14.7=24+14.7=38.7lb/in^2](https://tex.z-dn.net/?f=P_1%3DP%2B14.7%3D24%2B14.7%3D38.7lb%2Fin%5E2)
K=273+Degree Celsius
![T_1=3.4+273=276.4 K](https://tex.z-dn.net/?f=T_1%3D3.4%2B273%3D276.4%20K)
![T_2=26+273=299K](https://tex.z-dn.net/?f=T_2%3D26%2B273%3D299K)
![P_2=\frac{P_1T_2}{T_1}](https://tex.z-dn.net/?f=P_2%3D%5Cfrac%7BP_1T_2%7D%7BT_1%7D)
![P_2=\frac{38.7\times 299}{276.4}](https://tex.z-dn.net/?f=P_2%3D%5Cfrac%7B38.7%5Ctimes%20299%7D%7B276.4%7D)
![P_2=41.864 lb/in^2](https://tex.z-dn.net/?f=P_2%3D41.864%20lb%2Fin%5E2)
Gauge pressure in tire when the temperature rises to 26 degree Celsius.=![41.864-14.7=27.164lb/in^2](https://tex.z-dn.net/?f=41.864-14.7%3D27.164lb%2Fin%5E2)
The navigation rules entail vessels restricted in their ability to maneuver to display appropriate flag or lights. During the day of engagement of vessel in diving activities the rigid replica of the international code flag "ALPHA" must be exhibit not less than 3.3 feet while during night time the vessel must display the navigation light which is red and white and this requirement does not affect divers red and white flag which may be required by state to mark a divers location. The "A" flag is a kind of navigational signal which indicates the vessel’s restricted maneuverability and do not pertain to diver.
Answer:
d = 6.32 m
Explanation:
Given that,
The mass of a puck, m = 2 kg
It is pushed straight north with a constant force of 5N for 1.50 s and then let go.
We need to find the distance covered by the puck when move from rest in 2.25 s.
We know that,
F = ma
![a=\dfrac{F}{m}\\\\a=\dfrac{5}{2}\\\\a=2.5\ m/s^2](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7BF%7D%7Bm%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B5%7D%7B2%7D%5C%5C%5C%5Ca%3D2.5%5C%20m%2Fs%5E2)
Let d is the distance moved in 2.25 s. Using second equation of motion,
![d=ut+\dfrac{1}{2}at^2\\\\d=0+\dfrac{1}{2}\times 2.5\times (2.25)^2\\\\d=6.32\ m](https://tex.z-dn.net/?f=d%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5C%5Cd%3D0%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202.5%5Ctimes%20%282.25%29%5E2%5C%5C%5C%5Cd%3D6.32%5C%20m)
So, it will move 6.32 m from rest in 2.25 seconds.
Mutations typically cause an organism to be extinct would be the correct answer, most mutations occur when the organism is either damaged and is regeneration, or when the environment is too hostile for the organism, and it is trying to adapt.