As the collision frequency of gas particles increases, the mean free path of the gas particles decreases.
<h3>Frequency </h3>
The number of times a repeated event occurs in a given amount of time is known as its frequency. It is also sometimes called "temporal frequency" to stress the contrast to "spatial frequency" and "ordinary frequency" to underline the contrast to "angular frequency." Hertz (Hz), which is equal to one (event) per second, are the units used to express frequency. The reciprocal of frequency, the period is the length of time occupied by one cycle in a repeating event. When describing the temporal rate of change seen in oscillatory and periodic phenomena like mechanical vibrations, audio signals (sound), radio waves, and light, frequency is a crucial parameter utilized in science and engineering.
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Answer:
The two basic units of weight in the metric system is the?
The gram and kilogram is the Correct Answer...
Answer:
B. normal
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Answer:
Calculate the total distance travelled by the object - its motion is represented by the velocity-time graph below.
Here, the distance travelled can be found by calculating the total area of the shaded sections below the line.
½ × base × height.
½ × 4 × 8 = 16 m 2
(10 – 4) × 8 = 48 m 2
Explanation:
Solution :
a). B at the center :
![$=\frac{u\times I}{2R}$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7Bu%5Ctimes%20I%7D%7B2R%7D%24)
Here, one of the current is in the clockwise direction and therefore, the other current must be in the clockwise direction in order to cancel out the effect of the magnetic field that is produced by the other.
Therefore, the answer is ANTICLOCKWISE or COUNTERCLOCKWISE
b). Also, the sum of the fields must be zero.
Therefore,
![$\left(\frac{u\times I_1}{2R_1}\right) + \left(\frac{u\times I_2}{2R_2}\right) = 0$](https://tex.z-dn.net/?f=%24%5Cleft%28%5Cfrac%7Bu%5Ctimes%20I_1%7D%7B2R_1%7D%5Cright%29%20%2B%20%5Cleft%28%5Cfrac%7Bu%5Ctimes%20I_2%7D%7B2R_2%7D%5Cright%29%20%3D%200%24)
So,
![$\frac{I_1}{d_1}= \frac{I_2}{d_2}$](https://tex.z-dn.net/?f=%24%5Cfrac%7BI_1%7D%7Bd_1%7D%3D%20%5Cfrac%7BI_2%7D%7Bd_2%7D%24)
![$=\frac{16}{21}=\frac{I_2}{32}$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B16%7D%7B21%7D%3D%5Cfrac%7BI_2%7D%7B32%7D%24)
A
Therefore, the current in the outer wire is 24.38 ampere.