Answer:
Assuming the length to be x and the width to be y.
Since the area is 64cm, hence
x*y = 64 (equation 1)
Since the perimeter is 40cm, hence
x + x + y + y = 40
2x + 2y = 40
2(x + y) = 2(20)
x + y = 20 (equation 2)
Hence by using simultaneous equation,
x = 20 - y (equation 3)
Substituting equation 3 into equation 1, we get
(20-y)*y=64
20y-y^2=64
Tidying up the equation,
y^2 - 20y + 64 = 0
By using factorisation,
(y-16)(y-4)=0
y=16 or y=4
By substituting y=16 into equation 1,
x*16=64
x = 4
By substituting y = 4 into equation 1,
x*4=64
x=16
Therefore,
The length is 4 cm while the width is 16 cm.
OR
The length is 16 cm while the width is 4cm.
Hope this helps!!
Answer: A. The difference of the two means is significant at the 68% confidence level, so the null hypothesis must be rejected.
Step-by-step explanation:
I just got it right on PLATO, so I know it’s 100% correct.
Exact Form: 1991/2
Decimal Form: 995.5
Mixed Number Form: 995 1/2
change yrds to ft
5yds = 5*3 = 15 ft
5yds 2 ft = 15ft + 2ft = 17 ft
6yds = 6 * 3 = 18 ft
6 yds 1 ft = 18 + 1
19 ft
A = l * w
A = 17* 19
A = 323 ft^2
Choice A
