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Virty [35]
3 years ago
10

what height of a column of oil(p=850kg/m³) will be supported by atmospheric pressure of 60cm-hg?(p hg=13600kg/m³)​

Physics
1 answer:
galina1969 [7]3 years ago
4 0

Answer:

height of oil=60*13600/850=960 cm oil

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In all measurements and calculations, magnitude (number) and units are always included.
san4es73 [151]

the equation of the line allows us to find the answer is

            y = -27.8 t + 97.4

The equation of a line in a linear relationship between two variables, its general expression is

         y = A x + B

in this case the slope is the quantity that the independent variable in this case A = -27.8 m / s

The cut-off point that is the value of the dependent variable for x = is b = 97.4 m

In this case we see that the slope has a unit of [m / s] and the dependent variable is a unit of length, therefore the independent variable must have a unit of time [s] so that the entire equation is in units of length

          y = -27.8 t + 97.4

         [m] = [m / s] [s] + [m]

         [m] = [m]

The other two magnitudes with are necessary to write the equation r is the mean square root and gives an idea that the values ​​also fit the line, the best value is 1

In conclusion, the equation of the line allows us to find the answer is

            y = -27.8 t + 97.4

learn more about the equation inear here:

brainly.com/question/22851869

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3 years ago
A lunar module weighs 12 metric tons on the surface of the Earth. How much work is done in propelling the module from the surfac
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As we know that

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Work = F. dx

W=\int_{x_1}^{x_2}F.dx

W=\int_{1100}^{1140}\dfrac{2.4\times 10^6}{x^2}.dx

W=-2.4\times 10^6\left[\dfrac{1}{x}\right]_{1100}^{1140}

W=-2.4\times 10^6\left[\dfrac{1}{1140}-\dfrac{1}{1100}\right]

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