Liquid nitrogen<span> is </span>nitrogen<span> in a </span>liquid<span> state at an extremely low temperature. It is a colorless clear </span>liquid<span> with a density of 0.807 g/ml </span>
The average rate of formation of O2 is 4.225 × 10-4 M min-1
<h3>What is the equation of the reaction?</h3>
The equation of the reaction is given below:
From the equation of the reaction, 2 moles of Ibuprofen pentoxide decomposes to produce 1 mole of oxygen.
<h3>What is the average rate of formation of 02?</h3>
Rate of reaction is given as:
- Moles of product formed/moles of reactants used up/ time
- The ratio of mole of dinitrogen pentoxide decomposed to moles of oxygen produced is 2:1
Rate of disappearance of N2O5 = 8.45×10-4 M min-1.
Therefore, average rate of formation of O2 = 1/2 × 8.45×10-4 M min-1
Average rate of formation of O2 = 4.225 × 10-4 M min-1
Therefore, the average rate of formation of O2 is 4.225 × 10-4 M min-1
Learn more about rate of reaction at: brainly.com/question/24795637
Answer:
8.0 g
Explanation:
To convert moles to grams, you need to use the molar mass. The molar mass of sulfur is 32.06. The molar mass is the atomic mass of the atom.
(0.25 mol) × (32.06 g/mol) = 8.015 g
Round for significant figures.
8.015 g ≈ 8.0 g
Answer:
i am pretty sure the answer is a
Explanation: because the airplane's flight time has to be the independent variable for it to affect the dependent variable that is the speed of how fast the airplane is going.
Answer:
balanced equation mole ratio 5 2 mol NO/1 mol O2
10.00 g O2 3 1 mol O2/32.00 g O2 5 0.3125 mol O2
20.00 g NO 3 1 mol NO/30.01 g NO 5 0.6664 mol NO
actual mole ratio 5 0.6664 mol NO/0.3125 mol O2 5 2.132 mol NO/1.000 mol O2
Because the actual mole ratio of NO:O2 is larger than the balanced equation mole
ratio of NO:O2, there is an excess of NO; O2 is the limiting reactant.
Mass of NO used 5 0.3125 mol O2 3 2 mol NO/1 mol O2 5 0.6250 mol NO
0.6250 mol NO 3 30.01 g NO/1 mol NO 5 18.76 g NO
Mass of NO2 produced 5 0.6250 mol NO2 3 46.01 g NO2/1 mol NO2 5 28.76 g NO2
Excess NO 5 20.00 g NO 2 18.76 g NO 5 1.24 g N
Explanation:
