The expected freezing point of the solution is -12.01 °C
<h3>What is the freezing point of a substance?</h3>
The freezing point of a substance is the temperature at which a liquid changes to a solid.
When solutes are dissolved in solvents, they depress the freezing point of the solvent.
The expected freezing point of the solution is calculated using the formula;
where:
- ΔT = freezing point depression
- K = Freezing point constant
- m = molality of the solution
- i = Van't Hoff factor
For water, K = 1.86 ∘c/m
molality of solution = moles of solute/ mass of water in Kg
moles of NaCl = 85/58.5 = 1.453 moles
mass of water in kg = 450/1000 = 0.45
molality of solution = 1.453 / 0.45
molality of solution = 3.23 molal
i = 2
ΔT = 1.86 × 3.23 × 2
ΔT = 12.01
Freezing point of solution = Freezing point of water - ΔT
Freezing point of solution = 0 - 12.01
Freezing point of solution = -12.01 °C
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Answer:
kL, dL, mL, pL
Explanation:
pL stands for picoliters. This is equal to 1 × 10⁻¹² (0.000000000001) liters.
mL stands for milliliters. This is equal to 1 × 10⁻³ (0.001) liters.
dL stands for deciliters. This is equal to 1 × 10⁻¹ (0.1) liters.
kL stands for kiloliters. This is equal to 1 × 10³ (1000) liters.
Answer:
the pressure exerted in pascals is 0.5 Pa
Explanation:
The computation of the pressure exerted in pascals is shown below:
As we know that
Pressure = force ÷ area
= 25 ÷ 50
= 0.5 Pa
Hence, the pressure exerted in pascals is 0.5 Pa
We simply applied the above formula so that the correct pressure could come
