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2 years ago

Most of the energy released by nuclear fission is in the form of: alpha rays, beta rays, or gamma rays?

Physics

1 answer:

Sedbober [7]2 years ago

3 0

I think it is <span>Alpha rays.</span>

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What human process are carbon sources that are upsetting the balance between CO to update via planets and CO2 released by living

Serhud [2]

The combustion of fossil fuels is releasing more co2 into the atmosphere then what would occur naturally

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2 years ago

a car initially at 65.00 m/s accelerates at 22.39 m/s^2. How far has the car traveled before it comes to a stop

Gennadij [26K]

Answer:

94.35 meter

Step by step explanation

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2 years ago

Condominiums usually require a monthly fee for various services. At $235 a month, how much would a homeowner pay over a period o

Ivahew [28]

Answer:

$28200

Explanation:

Since 1 year has 12 months, 10 years have 120 months.

If one has to pay $235 a month, in 120 months one has to pay $235 done 120 times, which is the product of both numbers:

$P=($235)(120)=$28200$

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2 years ago

What factor affects sensation?

stiks02 [169]

The sensation differs between right and left. depending on what your under, pain,stress,sickness and sometimes possible death. <span />

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3 years ago

he block is released, and it slides 2.0 m (from the point at which it is released) across a horizontal surface before friction s

alex41 [277]

Answer:

0.245

Explanation:

When the block is released, the initial elastic potential energy stored in the spring is entirely converted into kinetic energy of the block.

Therefore, we can calculate the initial speed of the block:

$\frac{1}{2}kx^2 = \frac{1}{2}mv^2$

where the term on the left is the potential energy and where the term on the right is the kinetic energy, and where

k = 4500 N/m is the spring constant

x = 8.0 cm = 0.08 m is the compression of the spring

m = 3.0 kg is the mass of the block

v is the initial velocity

Solving for v,

$v=\sqrt{\frac{kx^2}{m}}=\sqrt{\frac{(4500)(0.08)^2}{3.0}}=3.1 m/s$

Then, after the block is released, all its kinetic energy is converted into thermal energy as the block slows down, due to friction. Therefore, the work done by friction is equal to the initial kinetic energy of the block.

The force of friction is

$F=\mu mg$

where

$\mu$ is the coefficient of friction

$g=9.8 m/s^2$ is the acceleration of gravity

So the work done by it is (in magnitude)

$W=Fd=\mu mg d$

where

d = 2.0 m is the distance covered

Therefore,

$\frac{1}{2}mv^2 = \mu mg d$

And solving for $\mu$ ,

$\mu = \frac{v^2}{2gd}=\frac{3.1^2}{2(9.8)(2.0)}=0.245$

8 0

2 years ago