Most of the energy released by nuclear fission is in the form of: alpha rays, beta rays, or gamma rays?
1 answer:
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Answer:
The specific question is not stated, however the general idea is given in the attached picture. The electric field in each region can be found by Gauss’ Law.
at r < R:
Since the solid sphere is conducting, the total charge Q is distributed over the surface, and the electric field inside the sphere is zero.
E = 0.
at R < r < 2R:
The electric field can be found by Gauss’ Law as in the attachment. The green pencil shows this exact region.
at 2R < r:
The electric field can again be found by Gauss’ Law, the blue pencil shows the calculations for this region.
Explanation:
Gauss’ Law is straightforward when applied to spheres. The area of the sphere is , and the enclosed charge is given in the question as Q for the inner sphere, and 2Q for the whole system.
The radius of a nucleus of hydrogen is approximately 
, while we can use the Borh radius as the distance of an electron from the nucleus in a hydrogen atom: 
The radius of a dime is approximately
: if we assume that the radius of the nucleus is exactly this value, then we can find how far is the electron by using the proportion
from which we find
So, if the nucleus had the size of a dime, we would find the electron approximately 500 meters away.
The radius of a dime is approximately
from which we find
So, if the nucleus had the size of a dime, we would find the electron approximately 500 meters away.