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olga55 [171]
3 years ago
7

Most of the energy released by nuclear fission is in the form of: alpha rays, beta rays, or gamma rays?

Physics
1 answer:
Sedbober [7]3 years ago
3 0
I think it is <span>Alpha rays.</span>
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WILL MARK BRAINLIESTFor the simple harmonic motion equation d =4sin(8pit) what is the period?
shtirl [24]
The period of any wave is the time it takes for its angle
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The 'sin' function is a wave.  The angle of this one is (8pi t).

When t=0, the angle is zero.
Wonderful.
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I*n other words, when is (8pi t) = 2pi ?

Divide each side by '2pi': . . . . . 4 t = 1

Divide each side by ' 4 ': . . . . . t = 1/4

And there you are.  Every time 't' grows by 1/4, (8pi t) grows by 2pi.
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3 years ago
Can some answer 7 a and b please
pav-90 [236]

Answer:

a.After 15 second Mr Comer's speed =  1.7 m/s

b.Distance travelled by Mr.Comer in 15 seconds  =   18.75\ m

Explanation:

a. Lets recall our first equation of motion V_{f} =V_{i} + at

Now we know that V_{i} = 0.8m/s , a = 0.06\ m/s^2 and

t = 15 \ sec

Plugging the values we have.

V_{f} =V_{i} + at

V_{f} =0.8 + 0.06 \times 15

V_{f} =0.8+ 0.9

V_{f} =1.7 m/s

Then Mr.Comer's speed after 15 sec = 1.7ms^-1

b.

Lets find the distance and recall our third equation of motion.

V_{f} ^2-V{i}^2 = 2as

So s = distance covered.

Dividing both sides with 2a we have.

\frac{V_{f} ^2-V{i}^2}{2a} = 2as

Plugging the values.

\frac{(1.7)^2-(0.8)^2}{2\times0.06} = 2as

s= 18.75\ m

So Mr.Comer will travel a distance of s= 18.75\ m.

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