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densk [106]
4 years ago
9

PLZZ HELP ASAp PLAAAAOSOZOZOSO

Chemistry
1 answer:
alexandr1967 [171]4 years ago
3 0

Answer:

5.Outer Core

Explanation:

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Calculate the quantity of energy produced per gram of U-235 (atomic mass = 235.043922 amu) for the neutron-induced fission of U-
Alexus [3.1K]

Answer:

To calculate the amount of energy produced per gram from Uranium- 235 we call on the formula:

delta(m)= mass of the products - mass of reactants

Given the atomic mass of Xe-144 = 143.9385 amu; atomic mass of Sr-90= 89.907738 amu;  atomic mass of  U-235= 235.043922 amu

Therefore:

delta(m)=  (143.9385 + 89.907738) - (235.043922)  = -1.197682 amu

Recall that to calculate energy in joules, we use the formula:

Energy = mc^2

Therefore: Energy = (-1.197582/6.022 x 10^26)kg x (3 x 10^8 m/s)^2

= -1.7898104 x 10^-10 J

= (-1.7898104 x 10^-10 x 6.022 x 10^23/235.043922)

= -4.586 x 10^11 J per gram of  energy released

Explanation:

To calculate the amount of energy produced per gram from Uranium- 235 we call on the formula:

delta(m)= mass of the products - mass of reactants

Given the atomic mass of Xe-144 = 143.9385 amu; atomic mass of Sr-90= 89.907738 amu;  atomic mass of  U-235= 235.043922 amu

Therefore:

delta(m)=  (143.9385 + 89.907738) - (235.043922)  = -1.197682 amu

Recall that to calculate energy in joules, we use the formula:

Energy = mc^2

Therefore: Energy = (-1.197582/6.022 x 10^26)kg x (3 x 10^8 m/s)^2

= -1.7898104 x 10^-10 J

= (-1.7898104 x 10^-10 x 6.022 x 10^23/235.043922)

= -4.586 x 10^11 J per gram of  energy released

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