I think it would be Newton’s second law
Using the 3rd equation of motion:
= v² - u² = 2gs ------ [g = Acceleration due to gravity]
= v² - 20² = 2 × 10 × 300
= v² - 400 = 6000
= v² = 6000 - 400
= v = √5600
= v = 74.83 m/s
And yeah it's done :)
Ok so the expression that you will be doing is water-water+object. The actual expression is 120-80. The answer would be 40mL. Remember, don't forget your units! :)
Answer:
a
Generally from third equation of motion we have that
![v^2 = u^2 + 2a[s_i - s_f]](https://tex.z-dn.net/?f=v%5E2%20%3D%20%20u%5E2%20%2B%202a%5Bs_i%20-%20s_f%5D%20)
Here v is the final speed of the car
u is the initial speed of the car which is zero
is the initial position of the car which is certain height H
is the final position of the car which is zero meters (i.e the ground)
a is the acceleration due to gravity which is g
So
![v^2 = 0 + 2g[H - 0]](https://tex.z-dn.net/?f=v%5E2%20%3D%200%20%2B%202g%5BH%20-%200%5D%20)
=> 
b
Explanation:
Generally from third equation of motion we have that
Here v is the final speed of the car
u is the initial speed of the car which is zero
is the initial position of the car which is certain height H
is the final position of the car which is zero meters (i.e the ground)
a is the acceleration due to gravity which is g
So
=>
When 
we have that
=> 
=>
Answer:
It should be A. Disturbance that travels through a medium or space, transmitting energy from one point to another.
I hope this helped you :)
