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Lunna [17]
3 years ago
5

How does the size of arctic foxes ears help to keep them warm in a cold environment

Physics
1 answer:
DochEvi [55]3 years ago
3 0
artic foxes have thick white fur to keep them warm and also for camouflage in the snow they have small ears to keep the snow out of their ears so that they can hear better they also have thick fur lining and a thick pad on their feet this stops the paws from getting cold and they have short legs so then the body weight can be spread making it easier for the animal to not sink in the snow in the summer the artic fox turns brown to help make the fox invisible when people are hunting in the long grass
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Help help help help help
nalin [4]
I am not sure on the rest but the answer to question 4 is volts. sorry i couldn’t be of more help!
3 0
3 years ago
A person is standing outdoors in the shade where the temperature is 17 °C. (a) What is the radiant energy absorbed per second by
Inessa05 [86]

Answer:

a) 4.9W b) 3.82W

Explanation:

Stefan-Boltzmann law of radiation formulae:

Q/t (W) = sigma* e*A*T^4

Sigma = 5.67*10^-8 j/sm^2K^4 (Stefano Boltzmann constant)

e = emissivity

T = absolute temperature in kelvin and A = area in m^2

a) Q/t = 140/10000(m^2) * 0.87* 5.67* 10^-8* (290^4) = 4.9W

b) without hair the

Q/t = 140/ 10000(m^2) *0.68* 5.67* 10^-8* (290^4)

= 3.82W

7 0
4 years ago
Water at 20 C flows through a 5-cm-diameter pipe that has a 180 vertical bend, as in Fig. P3.43. The total length of pipe betwee
Nataliya [291]

Answer:

F = 749 [N]

Explanation:

We must give full information on this problem, as well as the question that needs to be resolved.

Water at 20°C flows through a 5-cm-diameter pipe that has a 180° vertical bend. The total length of pipe between flanges 1 and 2 is 75 cm. When the weight flow rate is 230 N/s,

P1=165kPa

and

P2=134kPa

Neglecting pipe weight, determine the total force that the flanges must withstand for this flow.

We must make a U-shaped body diagram of the pipe in order to visualize the forces acting according to the pressures and the area of the pipe.

Then by means of the second law of motion of Newton, which says that the sum of the forces must be equal to the product of mass times acceleration, we can find the force Fp

Let us remember that pressure is defined as the divided force over the area, therefore:

F = P *A

where:

P = pressure

A = area

The product of the mass by acceleration, is equal to the product of the speed of the fluid by the mass flow, since we know the weight of the fluid we can find its mass flow.

W_{flow}=230[N/s]\\W_{flow} =g*m_{flow}\\m_{flow} = W_{flow} / g\\m_{flow} = 230/9.81\\m_{flow}= 23.45[kg/s]

In the function of the mass flow, we can find the velocity of the fluid, as we also know the diameter of the pipe

m_{flow} = density*v*A\\where\\density = 1000[kg/m^{3}]\\ v= velocity[m/s]\\A = area [m^{2}]\\v=\frac{m_{flow}}{density*A} \\v=\frac{23.45}{1000*\frac{\pi}{4}*(5*10^{-2})^{2} } \\v= 11.94 [m/s]

We know that the atmospheric pressure is equal to:

P_{atm} = 101.325[kpa]

The value of the pipe area is calculated for a circular section

A = \frac{\pi}{4} * (0.05)^{2}\\ A = 0.00196[m^{2} ]

The resultant force is 749 [N]

The solution of the equations and the free body diagram can be seen in the attached picture.

3 0
3 years ago
Iron filings were sprinkled around these two magnets. What do the iron filings
Sever21 [200]

Answer:

B. They show the pattern made by the magnetic field lines around the

magnets

Explanation:

Using iron fillings, the pattern of the magnetic field lines around a bar magnet can be known.

Magnetic field lines are the line of force around a bar magnet.

  • These iron fillings will trace the pattern of the magnetic field around the magnet.
  • The domains of the iron fillings begins to align and orient with that of the prevailing magnetic field around.
  • Those areas with the strongest force will attract more fillings and those far away will attract lesser fillings.
3 0
3 years ago
Read 2 more answers
The lengthening of a transmitted signal's wavelength and/or a decrease in its frequency, which indicates that the object is movi
andreyandreev [35.5K]
Both the effects (l<span>engthening of the transmitted signal's wavelength and decrease in its frequency) indicates that the object is moving away from the observer, and this phenomenon is called Doppler effect.

In fact, when the object is moving away from the observer, the relative distance between two consecutive crests of the wave emitted by the object increases to the observer eyes, since he's moving away. This means that the wavelength appears larger, and since the frequency is inversely proportional to the wavelength, the frequency appears smaller.</span>
3 0
4 years ago
Read 2 more answers
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