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3 years ago

How high can water be theoretically lifted by a vacuum pump at sea level?

Physics

1 answer:

Aleonysh [2.5K]3 years ago

7 0

Explanation:

everything can be found in the picture

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Difference between text-talk novel and flash fiction?

amid [387]

See the flash fictions are small nov.els with para.graphs where as ch*.t story is a storyline that just look like some c

c.h.*.t.s.

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2 years ago

The object falls faster at the pole then the equator why

natita [175]

Answer:

Due to sequential gravitation

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4 years ago

A supercapacitor is an electrical energy storage device. A supercapacitor, initially charged to 2.1 thousand millivolts, supplie

svet-max [94.6K]

Answer:

the time taken t is 9.25 minutes

Explanation:

Given the data in the question;

The initial charge on the supercapacitor = 2.1 × 10³ mV = 2.1 V

now, every minute, the charge lost is 9.9 %

so we need to find the time for which the charge drops below 800 mV or 0.8 V

to get the time, we can use the formula for compound interest in basic mathematics;

A = P × ( (1 - r/100 )ⁿ

where A IS 0.8, P is 2.1, r is 9.9

so we substitute

0.8 = 2.1 × ( 1 - 0.099 )ⁿ

0.8/2.1 = 0.901ⁿ

0.901ⁿ = 0.381

n = 9.25 minutes

Therefore, the time taken t is 9.25 minutes

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3 years ago

Two pulses are moving along a string. One pulse is

raketka [301]

Answer:

The answer is the 3rd option!

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3 years ago

A straight, cylindrical wire lying along the x axis has a length L and a diameter d . It is made of a material described by Ohm'

Zepler [3.9K]

The magnitude and direction of the electric field in the wire are mathematically given as

$L &=[(v / L) v / m] \hat{i}$

<h3>What is the magnitude and direction of the electric field in the wire?</h3>

Generally, the equation for is mathematically given as

A cylindrical wire that is straight and parallel to the x-axis has the following dimensions: length L, diameter d, resistivity p, diameter d, potential v, and z length. combining elements from both sides

E d $x=\int d v.$

$\begin{aligned}&-E \int_0^L d x=\int_v^0 d v \\\therefore E \cdot L &=v \\L &=[(v / L) v / m] \hat{i}\end{aligned}$

In conclusion, the magnitude and direction of the electric field in the wire are given as

$L &=[(v / L) v / m]$