Where is the airhorn of a 2014 kenworth t700?

Entrence is one of the animation category

krek1111 [17]

Answer:Videos

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Choosing a style of entrance animation effects | Microsoft ...

Jun 7, 2015

Video result for entrance is one of the animation category

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Video: Animate text - PowerPoint

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Explanation:

3 0

3 years ago

When discussing universal joints,

g100num [7]

Answer:

B only

Explanation:

7 0

4 years ago

Consider a piston-cylinder device with a piston surface area of 0.1 m^2 initially filled with 0.05 m^3 of saturated water vapor

miv72 [106K]

The friction force f = 10000 N

The heat transfer Q = 1.7936 KJ

<u>Explanation:</u>

Given data:

Surface area of Piston = 1 $m^{2}$

Volume of saturated water vapor = 100 K Pa

Steam volume = 0.05 $m^{3}$

Using the table of steam at 100 K pa

Steam density = 0.590 Kg/ $m^{3}$

Specific heat $C_{p}$ = 2.0267 KJ/Kg K

Mass of vapor = S × V

m = 0.590 × 0.05

m = 0.0295 Kg

Solution:

a) The friction force is calculated

Friction force = In the given situation, the force need to stuck the piston.

= pressure inside the cylinder × piston area

= 100 × $10^{3}$ × 0.1

f = 10000 N

b) To calculate heat transfer.

Heat transfer = Heat needs drop temperatures 30°C.

$Q=m c_{p} \ DT$

Q = 0.0295 × 2.0267 × $10^{3}$ × 30

Q = 1.7936 KJ

3 0

3 years ago

Given an integer k, a set C of n cities c1, . . . , cn, and the distances between these cities dij = d(ci , cj ), for 1 â¤ i &lt

Snezhnost [94]

Answer:

See explaination

Explanation:

2-Approximation Algorithm

Step 1: Choose any one city from the given set of cities C arbitrarily and put it in to a set H which is initially empty.

Step 2: For every city c in set C that is currently not present in set H compute min_distc = Minimum[ d(c, c1), d(c, c2), d(c, c3), ..... . . . . d(c, ci) ]

where c1, c2, ... ci are the cities in set H

and d(x, y) is the euclidean distance between city x and city y

Step 3: H = H ∪ {cx} where cx is the city have maximum value of min_dist over all possible cities c, computed in Step-2.

Step 4: Step-2 and Step-3 are iterated for k-1 times so that k cities are included int set H.

The set H is the required set of cities.

Example

Assume:-

C = {0, 1, 2, 3}

d(0,1) = 10, d(0,2) = 7, d(0,3) = 6, d(1,2) = 8, d(1,3) = 5, d(2,3) = 12

k = 3

Solution:-

Initially H = { }

Step-1: H = {0}

Step-2: Cities c \not\in H are {1, 2, 3}

min_dist1 = min{dist(0,1)} = min{10} = 10

min_dist2 = min{dist(0,2)} = min{7} = 7

min_dist3 = min{dist(0,3)} = min{6} = 6

Step-3: Max{10, 7, 6} = 10

Step-4: cx = 1

Step-5: H = H ∪ cx = {0} \cup {1} = {0, 1}

Step-6: Cities c \not\in H are {2, 3}

min_dist2 = min{dist(0,2), dist(1,2)} = min{7, 8} = 7

min_dist3 = min{dist(0,3), dist(1,3)} = min{6, 5} = 5

Step-7: Max{7, 5} = 7

Step-8: cx = 2

Step-9: H = H \cup cx = {0, 1} \cup {2} = {0, 1, 2}

Result: The set H is {0, 1, 2}.

6 0

3 years ago

Help please? this math is way too difficult

hoa [83]

Answer:

makin this,ill help with your math

Explanation:

6 0

3 years ago