Answer: precipitation of
from
and
ions in solution
Explanation:
Entropy is the measure of randomness or disorder of a system. If a system moves from an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.
is positive when randomness increases and
is negative when randomness decreases.
a) precipitation of
from
and
ions in solution : As ions are getting solidified, entropy decreases.
b) dissolution of
in water: The compounds dissociates into ions, entropy increases.
c) melting solid gold into liquid gold: The randomness increases, entropy increases.
d) evaporation of Hg(l) to form Hg(g) : The randomness increases, entropy increases.
e) mixing of two gases into one container : The randomness increases, entropy increases.
Answer:
this quote could best be used to describe the fellings that began which political
Explanation:
Answer:
Explanation:
The second best answer is likely well water. But it is possible that well water can be contaminated as well with soluble minerals.
See water would have salt in it which would make it hard to use.
River water could be containing dirt which would make washing hard to do.
Rain water is likely the best water to use.
Answer:
386.75 grams
Explanation:
You can use dimensional analysis to help you solve for this question
1. set up a proportion
<u> x grams</u>
4.25 mol x x mole
2. to find the amount of grams/mol that are in NiS we find the gram formula mass (mass of all the atomic masses of each element)
Ni- 59 grams
S- 32 grams
add these together and you get 91 g/mol
3. now plug in the values and multiply across
<u> 91 grams </u>
4.25 mol x 1 mole
when you multiply across this is equal to 386.75 grams
The number of moles of b2o3 that will be formed is determined as 4 moles.
<h3>
Limiting reagent</h3>
The limiting reagent is the reactant that will be completely used up.
4 b + 3O₂ → 2b₂O₃
from the equation above;
4 b ------------> 2 b₂O₃
2b ------------> b₂O₃
2 : 1
3O₂ -------------> 2b₂O₃
3 : 2
b is the limiting reagent, thus, the amount of b2o3 to be formed is calculated as;
4 b ------------> 2 moles of b2o3
8 moles -------> ?
= (8 x 2)/4
= 4 moles
Thus, the number of moles of b2o3 that will be formed is determined as 4 moles.
Learn more about limiting reactants here: brainly.com/question/14222359
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