A visible white and red light indicate a second craft is coming from the starboard (right) side.
<h3>What is a navigation light?</h3>
A navigation light often referred to as a running light or position light, is a source of illumination aboard a ship, plane, or spacecraft that provides information about the location, course, or condition of the vehicle. Red and green navigation lights help with traffic control by indicating the orientation of the craft.
All navigation light systems typically comprise one or more white lights as well as red and green sidelights that designate the boat's port and starboard sides.
Having a flashlight on board is also essential since you never know when a navigation light may go out.
The typical navigational lights:
SidelightsSternlightMasthead lampoverall white lighting
Sidelights: Because they are visible to other vessels approaching from the side or head-on, these red and green lights are sometimes known as combo lights. The port (left) and starboard (right) sides of a ship are indicated by the red and green lights, respectively.
sternlight: Only from behind or almost behind the ship can one see the sternlight.
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Answer:
fossil fuels are petroleum and natural gas. Well Fossils are mineralized remains of ancient plants and animals
Answer:
- The difference in length for steel is 2.46 x 10⁻⁴ m
- The difference in length for invar is 1.845 x 10⁻⁵ m
Explanation:
Given;
original length of steel, L₁ = 1.00 m
original length of invar, L₁ = 1.00 m
coefficients of volume expansion for steel, = 3.6 × 10⁻⁵ /°C
coefficients of volume expansion for invar, = 2.7 × 10⁻⁶ /°C
temperature rise in both meter stick, θ = 20.5°C
Difference in length, can be calculated as:
L₂ = L₁ (1 + αθ)
L₂ = L₁ + L₁αθ
L₂ - L₁ = L₁αθ
ΔL = L₁αθ
Where;
ΔL is difference in length
α is linear expansivity =
Difference in length, for steel at 20.5°C:
ΔL = L₁αθ
Given;
L₁ = 1.00 m
θ = 20.5°C
ΔL = 1 x 1.2 x 10⁻⁵ x 20.5 = 2.46 x 10⁻⁴ m
Difference in length, for invar at 20.5°C:
ΔL = L₁αθ
Given;
L₁ = 1.00 m
θ = 20.5°C
ΔL = 1 x 0.9 x 10⁻⁶ x 20.5 = 1.845 x 10⁻⁵ m
Answer:
S = V t - 1/2 a t^2 a here is negative due to deceleration
S = 4 * 8 - 1/2 * 64 = 0
The object just returns to its original starting point
It started out at 8 m/s which was reduced to 0 m/s after 4 sec
In 4 more seconds it was moving at -8 m/s, just the opposite of where it started
Answer:
Explanation:
To estimate the focal length of a convex lens follow the following steps.
1. take a convex lens.
2. Stand near a window which is just opposite to a wall.
3. Look at a tree which is far away from the window by the convex lens.
4. focus the image of the tree on the wall which is opposite to the window.
5. You wll observe that by changing the position of convex lens a sharp and inverted and small image is seen on the wall.
5. Now measure the distance between the lens and the wall.
7. This distance is the rough focal length of the convex lens.