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Marat540 [252]
2 years ago
10

A 90.0-kg mail bag hangs by a vertical rope 3.5 m long. A postal worker then displaces the bag to a position 2.0 m sideways from

its original position, always keeping the rope taut. (a) What horizontal force is necessary to hold the bag in the new position
Physics
1 answer:
asambeis [7]2 years ago
3 0

Answer:

615 N

Explanation:

If θ is the angle from vertical and T is the rope tension

θ = arcsin (2.0 / 3.5) = 34.85°

Summing vertical forces to zero

Tcosθ - mg = 0

T = 90.0(9.81) / cos34.85 = 1,075.85 N

Summing horizontal forces to zero

F - Tsinθ = 0

F = 1075.85sin34.85 = 1075.85(2.0/3.5) = 614.772... ≈ 615 N

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Find Displacement and Distance

displacement ...

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west is 600m

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3 years ago
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Answer:

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3 years ago
A 24 kg child slides down a 3.3-m-high playground slide. She starts from rest, and her speed at the bottom is 3.0 m/s.a. What en
Gelneren [198K]

Answer:

(a) Potential energy of the child is converted into the kinetic energy at the bottom off the slide and a part of which is lost into friction generating heat between the contact surfaces.

(b) U=668.16\ J

Explanation:

Given:

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  • height of the slide, h=3.3\ m
  • initial velocity of the child at the slide, v_i=0 m.s^{-1}
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(a)

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Initial potential energy:

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(b)

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