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Katena32 [7]
3 years ago
11

HELP! Can an object that is in motion have balanced forces? Explain your answer

Physics
1 answer:
Elan Coil [88]3 years ago
6 0

Answer:

Yes.

Explanation:

Newton's first law says that an object in motion stays in motion and an object at rest stays at rest until acted upon by an unbalanced force.

If an object in motion has balanced forces, it will stay in motion.  For example, if an object is falling at terminal velocity (for example, a parachuter), then the force of gravity is equal and opposite to the force of air resistance.  The forces are balanced, and the object continues to fall at a constant speed.

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A small metal object is tied to the end of a string and whirled round a circular path of radius 30cm. The object makes 20 oscill
LUCKY_DIMON [66]

Answer:

(i) The angular speed of the small metal object is 25.133 rad/s

(ii) The linear speed of the small metal object is 7.54 m/s.

Explanation:

Given;

radius of the circular path, r = 30 cm = 0.3 m

number of revolutions, n = 20

time of motion, t = 5 s

(i) The angular speed of the small metal object is calculated as;

\omega = \frac{20 \ rev}{5 \ s} \times \frac{2 \pi \ rad}{1 \ rev} = \frac{40\pi \ rad}{5 \ s} = 8\pi \ rad/s = 25.133 \ rad/s

(ii) The linear speed of the small metal object is calculated as;

v = \omega r\\\\v = 25.133 \ rad/s \ \times \ 0.3 \ m\\\\v = 7.54 \ m/s

6 0
3 years ago
When Bella pushes a box with a mass of 5.25 kilograms with a force of 15.75 newtons, it accelerates at a rate of 2.5 meters/seco
Mariana [72]

Sure !

Start with Newton's second law of motion:

                     Net Force = (mass) x (acceleration) .

This formula is so useful, and so easy, that you really
should memorize it.

Now, watch:

The mass of the box is 5.25 kilograms, and the box is
accelerating at the rate of  2.5 m/s² .
What's the net force on the box ?

                    Net Force = (mass) x (acceleration)

                                     = (5.25 kilograms) x (2.5 m/s²)

                     Net force =       13.125 newtons .

But hold up, hee haw, whoa !  Wait a second !
Bella is pushing with a force of 15.75 newtons, but the box
is accelerating as if the force on it is only 13.125 newtons.
What happened to the rest of Bella's force ? ?

==>  Friction is pushing the box in the opposite direction,
and cancelling some of Bella's force.

How much ?

            (Bella's 15.75 newtons) minus (13.125 that the box feels)

           =      2.625 newtons backwards, applied by friction.


5 0
3 years ago
Read 2 more answers
A car travels 45 km north. It then turns around and travels 30 km south. What is the car's displacement?
natka813 [3]
If the ration supplementary angle is 11:7,find the measure of the larger angle larger angle?
4 0
3 years ago
The Earth’s radius is 6378.1 kilometers. If you were standing at the equator, you are essentially undergoing uniform circular mo
emmainna [20.7K]

Answer:

b. 84 minutes

Explanation:

a_c=g = Centripetal acceleration = 9.81 m/s²

r = Radius of Earth = 6378.1 km

v = Velocity

Centripetal acceleration is given by

a_c=\dfrac{v^2}{r}\\\Rightarrow v=\sqrt{a_cr}\\\Rightarrow v=\sqrt{9.81\times 6378100}\\\Rightarrow v=7910.06706\ m/s

Time period is given by

T=\dfrac{2\pi r}{v60}\\\Rightarrow T=\dfrac{2\pi 6378.1\times 10^3}{7910.06706\times 60}\\\Rightarrow T=84.43835\ minutes

The time period of Earth’s rotation would be 84.43835 minutes

7 0
3 years ago
A hockey puck sliding on smooth ice at 4 m/s comes to a 1-m-high hill. Will it make it to the top of the hill?
solniwko [45]

Answer:

No  it will not make to the top of the hill  

Explanation:

From the question we are told that

   The velocity is  v  =  4 \ m/s

    The height of the hill is  h  = 1 \  m

Generally from the law of energy conservation we have that

   The kinetic energy of the pluck at the level position =  The potential energy of the pluck at the maximum height the  pluck can get  to  

So

       \frac{1}{2}  * m * v^2 =  m *  g *  h_{max}

=>    \frac{1}{2}   * v^2 =    g *  h_{max}

=>     h_{max} =   \frac{0.5 * v^2}{g}

=>     h_{max} =  0.8163 \  m

Given that the maximum height which the pluck can get to at this speed given in the question is less than the height of the hill then conclusion will be that the pluck will not make it to the top of the hill

     

3 0
3 years ago
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