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Darya [45]
3 years ago
8

An object with mass 'm' is moving in a circle of radius 'R' at a constant speed of 'v.' The acceleration of the object will INCR

EASE if _____. List all that apply ... .
Physics
1 answer:
xenn [34]3 years ago
5 0

Answer:

Explanation:

The acceleration of an object is given by the formula

a = v²/r

The acceleration of the object is bound to increase, if and only if the following are changed as well.

The mass of the object is increased,

The speed of the object is increased,

The radius of the object is contrarily decreased

Taking another look at the formula, we see that if we increase the speed of the object, it increases the acceleration. And since the radius is in the denominator, it has to be reduced for the acceleration to increase

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Photons with shorter wavelengths have larger
Zarrin [17]

i think photons with shorter wavelengths have larger speed.

I apologise if its incorrect.

7 0
3 years ago
A positively charged particle Q1 = +35nC is held fixed at the origin. A second charge of mass m = 3.5ug is floating a distance d
cupoosta [38]

Answer:

Explanation:

Q1 = 35 nC = 35 x 10^-9 C

m = 3.5 micro gram = 3.5 x 10^-9 Kg

d  = 35 cm = 0.35 m

(a) The electrostatic force between the two charges is balanced by the weight of another charge.

F = m g

\frac{1}{4\pi \epsilon _{0}}\frac{Q_{1}Q_{2}}{d^{2}}=mg

Q_{2}=\frac{4\pi \epsilon _{0}mgd^{2}}{Q_{1}}

(b) By substituting the values

Q_{2}=\frac{3.5\times 10^{-9}\times 9.8\times 0.35\timees 0.35}{9\times 10^{9}\times 35\times 10^{9}}

Q2 = 13.34 x 10^-12 C

Q2 = 0.0134 nC

4 0
3 years ago
We reduce friction in machines? why<br>​
kvv77 [185]

Answer:

friction reduces the efficiency of machines, thus we must reduce the friction force that is acting upon it.

5 0
3 years ago
Read 2 more answers
Please help me with this very easy question I just don’t get it.
diamong [38]

Answer:

150m

Explanation:

The relation of speed/time and distance/time is a derivative/integral one, as in speed is the derivative of distance (the faster you go, the faster the distance changes, duh!).

So we need to compute the integral of speed over time from 0.0s to 5.0s.

The easiest way here is to compute the area under the line (it's going to be faster than computing the acceleration and using a formula of distance based on acceleration).

The area under the line is a trapezoid with "height" 5s, and the bases 10m/s and 50m/s. Using the trapezoid area formula of h*(a + b)/2

distance = 5s * (10m/s + 50m/s) / 2 = 5s * 60m/s / 2 = 5s * 30m/s = 150m

Alternatively, we can use the acceleration formula:

a = (50m/s - 10m/s)/5s = 40m/s / 5s = 8m/s^2

distance = v0 * t + a * t^2 / 2 = 10m/s * 5s + 8m/s^2 * (5s)^2 / 2 = 50m + 8m * 25 / 2 = 50m + 100m = 150m.

5 0
2 years ago
The density of the Earth is greater than the density of an equal volume of water by _____.
defon

Answer:

I think the second option is correct

please mark me as brainliest

5 0
3 years ago
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