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Darya [45]
3 years ago
8

An object with mass 'm' is moving in a circle of radius 'R' at a constant speed of 'v.' The acceleration of the object will INCR

EASE if _____. List all that apply ... .
Physics
1 answer:
xenn [34]3 years ago
5 0

Answer:

Explanation:

The acceleration of an object is given by the formula

a = v²/r

The acceleration of the object is bound to increase, if and only if the following are changed as well.

The mass of the object is increased,

The speed of the object is increased,

The radius of the object is contrarily decreased

Taking another look at the formula, we see that if we increase the speed of the object, it increases the acceleration. And since the radius is in the denominator, it has to be reduced for the acceleration to increase

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The grant that considered the foundation of financial aid is the:
navik [9.2K]

Answer:

I think it is the Federal Pell Grant Program.

Explanation:

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2 years ago
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A Ferris wheel on a California pier is 27 m high and rotates once every 32 seconds in the counterclockwise direction. When the w
Leto [7]

A) 140 degrees

First of all, we need to find the angular velocity of the Ferris wheel. We know that its period is

T = 32 s

So the angular velocity is

\omega=\frac{2\pi}{T}=\frac{2\pi}{32 s}=0.20 rad/s

Assuming the wheel is moving at constant angular velocity, we can now calculate the angular displacement with respect to the initial position:

\theta= \omega t

and substituting t = 75 seconds, we find

\theta= (0.20 rad/s)(75 s)=15 rad

In degrees, it is

15 rad: x = 2\pi rad : 360^{\circ}\\
x=\frac{(15 rad)(360^{\circ})}{2\pi}=860^{\circ} = 140^{\circ}

So, the new position is 140 degrees from the initial position at the top.

B) 2.7 m/s

The tangential speed, v, of a point at the egde of the wheel is given by

v=\omega r

where we have

\omega=0.20 rad/s

r = d/2 = (27 m)/2=13.5 m is the radius of the wheel

Substituting into the equation, we find

v=(0.20 rad/s)(13.5 m)=2.7 m/s

6 0
3 years ago
Question 27 a motorboat takes 3 hours to travel 144km going upstream. the return trip takes 2 hours going downstream. what is th
Vedmedyk [2.9K]
In this item, we let x be the rate of the boat in still water and y be the rate of the current.

Upstream. When the boat is going upstream, the speed in still water is deducted by the speed of the current because the boat goes against the water. The distance covered is calculated by multiplying the number of hours and the speed.
                 (x - y)(3) = 144

Downstream. The speed of the boat going downstream is equal to x + y because the boat goes with the current.
                (x + y)(2) = 144

The system of linear equations we can use to solve for x is,
                  3x - 3y  = 144
                  2x + 2y = 144

We use either elimination or substitution.
 
We solve for the y of the first equation in terms of x,
                   y =  -(144 - 3x)/3

Substitute this to the second equation,
            2x + 2(-1)(144 - 3x)/3 = 144
The value of x from the equation is 60

<em>ANSWER: 60 km/h</em>
5 0
3 years ago
How would you respond to a person who argued that the Big Bang theory is incorrect because it is only a theory and theories have
Umnica [9.8K]

Well, you would reply that that's not what theories are. Theories explain the how and the why, laws explain the what. So, the Big Bang theory isn't "just a theory". It's a theory, it explains the how. (Also, if someone tells you it's anti-God or whatever, tell them the thoery was created by a Catholic scientist. True fact.) I hoped this helped!!! (You don't have the include who created the theory if this is for homework.)

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3 years ago
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Let’s tie this all together. It makes sense that, if the rope force remains greater than the gravitational force, the child keep
Pavlova-9 [17]

Answer:

If child weight is equal to rope force then child will move with uniform speed

or we can say that the child will remain at rest in his position

Explanation:

As we know that child is hanging by rope

so here there will be two forces on the child

1) Weight or gravitational force which act vertically downwards

2) Tension in the rope which act vertically upwards

Now if child will accelerate upwards then tension force must be more than the weight of the child

If tension force is less than the weight then child will decelerate and his speed will decrease

if tension force is equal to child weight then in that case the child will remain at rest or it will move with same speed

8 0
3 years ago
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