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3 years ago

What are the factors on which solubility depends? explain by giving examples

Chemistry

1 answer:

trasher [3.6K]3 years ago

4 0

Answer:

Solubility is the maximum amount of a substance that will dissolve in a given amount of solvent at a specific temperature. There are two direct factors that affect solubility: temperature and pressure. Temperature affects the solubility of both solids and gases, but pressure only affects the solubility of gases.

Explanation:

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How can you experimentally determine the pK_a of acetic acid? Determine the pH of the solution 1/4 of the way to the end-point o

Vlad1618 [11]

Answer:

Determine the pH of the solution half-way to the end-point on the pH titration curve for acetic acid.

Explanation:

The equation for the ionization of acetic acid is

HA + H₂O ⇌ H₃O⁺ + A⁻

For points between the starting and equivalence points, the pH is given by the Henderson-Hasselbalch equation:

$\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{[\text{A}^{-}]}{\text{[HA]}}$

At the half-way point, half of the HA has been converted to A⁻, so [HA] = [A⁻]. Then,

$\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{1}{1} = \text{pK}_{\text{a}} + 0 \\\\\text{pH} = \text{pK}_{\text{a}}$

The pKₐ is the pH at the half-way point in the titration.

8 0

3 years ago

The compound known as butylated hydroxytoluene, abbreviated as BHT, contains carbon, hydrogen, and oxygen. A 2.001 g sample of B

Alborosie

Answer: The empirical formula for the given compound is $C_{15}H_{24}O_1$

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen, iron and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=5.995g$

Mass of $H_2O=1.963g$

Mass of sample = 2.001 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 5.995 g of carbon dioxide, $\frac{12}{44}\times 5.995=1.635g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.963 g of water, $\frac{2}{18}\times 1.963=0.218g$ of hydrogen will be contained.

Mass of oxygen in the compound = (2.001) - (1.635 + 0.218) = 0.148 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.635g}{12g/mole}=0.136moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.218g}{1g/mole}=0.218moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.148g}{16g/mole}=0.0092moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0092 moles.

For Carbon = $\frac{0.136}{0.0092}=14.78\approx 15$

For Hydrogen = $\frac{0.218}{0.0092}=23.69\approx 24$

For Oxygen = $\frac{0.0092}{0.0092}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 15 : 24 : 1

Hence, the empirical formula for the given compound is $C_{15}H_{24}O_1$

3 0

4 years ago

Select The on that most applys Will mark brainliest

sdas [7]

Answer:

A and C

Explanation:

7 0

3 years ago

0.05 grams od cobalt ii oxalate will dissolve in one liter of solution at 25 degree celcius. Calculate the ksp for cobalt ii oxa

Veseljchak [2.6K]

Answer:

The equilibrium expression is:

CoC2O4(s)⇌Co2+(aq)+C2O2−4(aq)

For this reaction:

Ksp = [Co2+][C2O2−4]=1.96×10−8

Explanation:

Batteries will not clot if cobalt ions are removed from its cells. Some blood collection tubes contain salts of the oxalate ion,

C2O2−4

, for this purpose. At sufficiently high concentrations, the calcium

and oxalate ions form solid, CoC2O4·H2O (which also contains water bound in the solid). The concentration of Co2+ in a sample of blood serum is 2.2 × 10–3M. What concentration of

C2O2−4

ion must be established before CoC2O4·H2O begins to precipitate.

CoC2O4 does not appear in this expression because it is a solid. Water does not appear because it is the solvent.

Solid CoC2O4 does not begin to form until Q equals Ksp. Because we know Ksp and [Co2+], we can solve for the concentration of

C2O2−4

that is necessary to produce the first trace of solid:

5 0

3 years ago

Determine the freezing point of 0.368 kg of H2O with 11.85 g of C2H5OH where the kf is 1.86 C/m.

saveliy_v [14]

We will use the formula for freezing point depression :

but first, we need to get the molality m of the solution:

- molality m = moles of C2H5OH / mass of water Kg

when moles of C2H5OH = mass of C2H5OH/ molar mass of C2H5OH

= 11.85 g / 46 g/mol

= 0.258 moles

and when we have the mass of water Kg = 0.368 Kg

so, by substitution on the molality formula:

∴ molality m = 0.258 moles / 0.368 Kg

= 0.7 mol/Kg

and when C2H5OH is a weak acid so, there is no dissociation ∴ i = 1

and when Kf is given = 1.86 C/m

so by substitution on ΔTf formula:

when ΔTf = i Kf m

∴ ΔTf = 1 * 1.86C/m * 0.7mol/Kg

= 1.302 °C

5 0

3 years ago

What are the factors on which solubility depends? explain by giving examples​

What are the factors on which solubility depends? explain by giving examples