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2 years ago

Daniel steps on the gas pedal of his car, and the engine increases its performance from zero to

Physics

1 answer:

RSB [31]2 years ago

6 0

Answer

The frequency and the period are 45 cycles/second and 0.023 seconds

Explanation:

The frequency of the engine is given by :

$f=\dfrac{rpm}{60}$

We have, the engine increases its performance from zero to 2700 rpms.

Frequency,

$f=\dfrac{2700}{60}\ \text{cycles per second}\\\\f=45\ \text{cycles per second}$

The time period of the engine is given by :

T = f/f

So,

$T=\dfrac{1}{45}\ s\\\\T=0.023\ s$

Hence, the required frequency and the period are 45 cycles/second and 0.023 seconds respectively.

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