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jarptica [38.1K]
2 years ago
6

What temperature will 1L of H20 at 200°F become when a piece of copper,0.25kg at 260.928K, comes into contact with water?

Physics
1 answer:
Lady_Fox [76]2 years ago
7 0

Answer:

Explanation:

mass of 1 L water = 1 kg .

200⁰F = (200 - 32) x 5 / 9 = 93.33⁰C .

260.928 K = 260.928 - 273 = - 12.072⁰C .

water is at higher temperature .

Let the equilibrium temperature be t .

Heat lost by water = mass x specific heat x  fall of temperature

= 1 x 4.2 x 10³ x ( 93.33 - t )

Heat gained by copper

= .25 x .385 x 10³ x ( t +  12.072 )

Heat lost = heat gained

1 x 4.2 x 10³ x ( 93.33 - t ) = .25 x .385 x 10³ x ( t +  12.072 )

93.33 - t = .0229 ( t + 12.072)

93.33 - t = .0229 t + .276

93.054 = 1.0229 t

t = 90.97⁰C .

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Answer:

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Explanation:

<h2>Method 1: Impulse </h2>

We can solve this problem by using the impulse formula.

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<h2>Method 2: Newton's Second Law</h2>

The force that the car's tires exert on the road is equivalent to the force that the road exerts on the car due to Newton's Third Law of Motion.

We can calculate the force that the car's tires exert on the road by using the formula F = ma, which was derived from Newton's Second Law of Motion.

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We are given the mass of the car, velocity of the car, and the time in which it accelerated.

We can use this equation for acceleration:

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The car started from rest, meaning it had an initial velocity of 0 m/s. Its final velocity was 10 m/s. The time that it took for the car to go from 0 m/s to 10 m/s was 4.5 seconds.

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The force that the car's tires exert on the road is 2667 N.

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