Answer:
B, A, C, D
Explanation:
i hope it helps. im just kinda guessing.
good luck!°°°°°⁰⁰⁰⁰⁰₀₀₀₀₀oo00OO
Answer:
The frequency heard by the motorist is 4313.2 Hz.
Explanation:
let f1 be the frequency emited by the police car and f2 be the frequency heard by the motorist, let v1 be the speed of the police car and v2 be the speed of the motorist and v = 343 m/s be the speed of sound.
because the police car is moving towards the motorist at a higher speed, then the motorist will hear a increasing frequency and according to Dopper effect, that frequency is given by:
f1 = [(v + v2/(v - v1))]×(f2)
= [( 343 + 30)/(343 - 36)]×(3550)
= 4313.2 Hz
Therefore, the frequency heard by the motorist is 4313.2 Hz.
Answer:
Wmoon = 131 [N]
Explanation:
We know that the weight of a body is equal to the product of mass by gravitational acceleration.
Since we are told that the gravitational acceleration of the moon is equal to one-sixth of the acceleration of Earth's gravitation. Then we must multiply the value of Earth's gravitation by one-sixth.
![w_{moon}=\frac{1}{6} *m*g\\w_{moon}=\frac{1}{6} *80*9.81\\w_{moon}=130.8 [N] = 131 [N]](https://tex.z-dn.net/?f=w_%7Bmoon%7D%3D%5Cfrac%7B1%7D%7B6%7D%20%2Am%2Ag%5C%5Cw_%7Bmoon%7D%3D%5Cfrac%7B1%7D%7B6%7D%20%2A80%2A9.81%5C%5Cw_%7Bmoon%7D%3D130.8%20%5BN%5D%20%3D%20131%20%5BN%5D)
When the system is experiencing a uniformly accelerated motion, there are a set of equations to work from. In this case, work is energy which consist solely of kinetic energy. That is, 1/2*m*v2. First, let's find the final velocity.
a = (vf - v0)/t
2.6 = (vf - 0)/4
vf = 10.4 m/s
Then W = 1/2*(2100 kg)*(10.4 m/s)2
W = 113568 J = 113.57 kJ
The magnet needs to be held above the coils of wires
