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jarptica [38.1K]
2 years ago
6

What temperature will 1L of H20 at 200°F become when a piece of copper,0.25kg at 260.928K, comes into contact with water?

Physics
1 answer:
Lady_Fox [76]2 years ago
7 0

Answer:

Explanation:

mass of 1 L water = 1 kg .

200⁰F = (200 - 32) x 5 / 9 = 93.33⁰C .

260.928 K = 260.928 - 273 = - 12.072⁰C .

water is at higher temperature .

Let the equilibrium temperature be t .

Heat lost by water = mass x specific heat x  fall of temperature

= 1 x 4.2 x 10³ x ( 93.33 - t )

Heat gained by copper

= .25 x .385 x 10³ x ( t +  12.072 )

Heat lost = heat gained

1 x 4.2 x 10³ x ( 93.33 - t ) = .25 x .385 x 10³ x ( t +  12.072 )

93.33 - t = .0229 ( t + 12.072)

93.33 - t = .0229 t + .276

93.054 = 1.0229 t

t = 90.97⁰C .

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3 years ago
Nicole throws a ball at 25 m/s at an angle of 60 degrees abound the horizontal. What is the range of the ball?
just olya [345]

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the range or the ball is 48.81 m

Explanation:

given;

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solution:

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Vo = 25 m/s

<u>consider x-motion using time of fight: x = Vox * t</u>

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t =<u> 2 Voy </u>

      g

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           g

plugin values into the formula:

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4 0
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Read 2 more answers
What is the centripetal force for a roller coaster if the mass is 10 kg and the normal force is 25 N?
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Answer:

Fc = 123 Newton

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

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Fnet is the net force.

Fapp is the applied force.

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To find the centripetal force;

From the net force, we have the following formula;

Fc = N + mg

Where;

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mg is the the weight of the object.

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