Answer: Attached below is the well written question and solution
answer:
i) Attached below
ii) similar parameter = ![\frac{V}{VoL } = 1 / Re](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7BVoL%20%7D%20%3D%201%20%2F%20Re)
Explanation:
Using ; L as characteristic length and Vo as reference velocity
i) Nondimensionalize the equations
ii) Identifying similarity parameters
the similar parameters are = ![\frac{V}{VoL } = 1 / Re](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7BVoL%20%7D%20%3D%201%20%2F%20Re)
Attached below is the detailed solution
Answer:
The head loss in Psi is 0.390625 psi.
Explanation:
Fluid looses energy in the form of head loss. Fluid looses energy in the form of head loss when passes through the valve as well.
Given:
Factor cv is 48.
Flow rate of water is 30 GPM.
GPM means gallon per minute.
Calculation:
Step1
Expression for head loss for the water is given as follows:
![c_{v}=\frac{Q}{\sqrt{h}}](https://tex.z-dn.net/?f=c_%7Bv%7D%3D%5Cfrac%7BQ%7D%7B%5Csqrt%7Bh%7D%7D)
Here, cv is valve coefficient, Q is flow rate in GPM and h is head loss is psi.
Step2
Substitute 48 for cv and 30 for Q in above equation as follows:
![48=\frac{30}{\sqrt{h}}](https://tex.z-dn.net/?f=48%3D%5Cfrac%7B30%7D%7B%5Csqrt%7Bh%7D%7D)
![{\sqrt{h}}=0.625](https://tex.z-dn.net/?f=%7B%5Csqrt%7Bh%7D%7D%3D0.625)
h = 0.390625 psi.
Thus, the head loss in Psi is 0.390625 psi.
Answer:
d) Binary
Explanation:
Binary search is a search algorithm that finds the position of a value in an ordered array. It compares the value with the element in the middle of the array, if they are not equal, half in which the value cannot be eliminated and the search continues in the remaining half until the value is found.
Answer: 24 pA
Explanation:
As pure silicon is a semiconductor, the resistivity value is strongly dependent of temperature, as the main responsible for conductivity, the number of charge carriers (both electrons and holes) does.
Based on these considerations, we found that at room temperature, pure silicon resistivity can be approximated as 2.1. 10⁵ Ω cm.
The resistance R of a given resistor, is expressed by the following formula:
R = ρ L / A
Replacing by the values for resistivity, L and A, we have
R = 2.1. 10⁵ Ω cm. (10⁴ μm/cm). 50 μm/ 0.5 μm2
R = 2.1. 10¹¹ Ω
Assuming that we can apply Ohm´s Law, the current that would pass through this resistor for an applied voltage of 5 V, is as follows:
I = V/R = 5 V / 2.1.10¹¹ Ω = 2.38. 10⁻¹¹ A= 24 pA