Answer:
The current in the rods is 171.26 A.
Explanation:
Given that,
Length of rod = 0.85 m
Mass of rod = 0.073 kg
Distance 
The rods carry the same current in the same direction.
We need to calculate the current
I is the current through each of the wires then the force per unit length on each of them is
Using formula of force


Where, m = mass of rod
l = length of rod
Put the value into the formula




Hence, The current in the rods is 171.26 A.
The current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.
<h3>What current flows through the bulb as well as the power of the bulb?</h3>
From ohm's law; V = I × R
Where V is the voltage, I is the current and R is the resistance.
Also, Power is expressed as; P = V × I
Where V is voltage and I is current.
Given that;
- Resistance R = 10.0 ohms
- Voltage V = 12.0V
- Current I = ?
- Power P = ?
First, we determine the current flow through the bulb.
V = I × R
12.0V = I × 10.0 ohms
I = 12.0 ÷ 10.0
I = 1.2A
Next, we determine the power of the bulb.
P = V × I
P = 12.0V × 1.2A
P = 14.4 Watts
Therefore, the current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.
Learn more about Ohm's law here: brainly.com/question/12948166
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Answer:
Required materials for electroplating are - battery or electric supply, cathode, anode and salt solution of material to be coated. Electroplating is the process of releasing ions from electrolytes and coating them as atoms on required material.