If the length of a string increases 2 times but the mass of the string remains constant, the original density will be multiplied by a factor mathematically given as
v=1.414 times
<h3>Will the new density of the string equal the original density multiplied by what factor?</h3>Generally, the equation for the volume is mathematically given as
v = sqt(TL/m)
Where
density = mass/length
Therefore
In conclusion,v ratio will give us
v=1.414 times
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Explanation:
(a) The given data is as follows.
Load applied (P) = 1000 kg
Indentation produced (d) = 2.50 mm
BHI diameter (D) = 10 mm
Expression for Brinell Hardness is as follows.
HB =
Now, putting the given values into the above formula as follows.
HB = =
=
= 200
Therefore, the Brinell HArdness is 200.
(b) The given data is as follows.
Brinell Hardness = 300
Load (P) = 500 kg
BHI diameter (D) = 10 mm
Indentation produced (d) = ?
d =
=
= 4.46 mm
Hence, the diameter of an indentation to yield a hardness of 300 HB when a 500-kg load is used is 4.46 mm.