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Sonbull [250]
3 years ago
6

For the reaction shown, drsw the major(s) expected product.​

Chemistry
1 answer:
Andru [333]3 years ago
4 0

Answer:

2

Explanation:

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150 words describing Bohr’s model, and the fundamental principles behind it. Also, explain how Bohr’s model is different from Ru
luda_lava [24]
Bohr's model is different from Rutherford's model by Bohr's model has 150 words , fundamental principles. also Rutherford's model does not have 150 words and fundamental principles. <span />
8 0
3 years ago
17. An industrially important element contains
likoan [24]

Answer:

Iron (Fe)

Explanation:

The number of electrons (-) is usually the same as the number of protons (+) in the atom of the element (unless it is an ion).

The element described has 26 electrons, so we can assume that it has 26 protons as well. The number of protons in an atom is the atomic number of element that the atom is.

Element 26 on the PTE is Iron (Fe), which does rust (oxidation) in air and water.

8 0
3 years ago
The electron configuration of a neutral elerpent is 1s 2s 2p 3s. If the electron configuration
Alchen [17]

Answer:

Ne 2

Explanation:

8 0
3 years ago
Calculate the pH of a solution whose H3O+ concentration is 2.1 x 10-3 M. Is the solution acidc, basic, or neutral?
Leona [35]

Answer:

Option A, The pH of the solution is 2.7 and the solution is acidic

Explanation:

As we know,

pH =  - log [H3O+]

Substituting the given values, we get

pH =  - log [2.1 x 10-3 M]

pH =  - (-2.678)

pH = 2.678 or 2.7

The solution is acidic as pH value is less than 7

Hence, option A is correct

5 0
3 years ago
How many liters of oxygen gas, at standard
Karo-lina-s [1.5K]

Answer:

Explanation:

  • For the balanced reaction:

<em>4Fe(s) + 3O₂(g) → 2Fe₂O₃(s)​.</em>

It is clear that 4 mol of Fe react with 3 mol of O₂ to produce 2 mol of Fe₂O₃.

  • Firstly, we need to calculate the no. of moles of 35.8 grams of Fe metal:

no. of moles of Fe = mass/molar mass = (35.8 g)/(55.845 g/mol) = 0.64 mol.

  • Now, we can find the no. of moles of O₂ is needed to react with the proposed amount of Fe:

<em><u>Using cross multiplication:</u></em>

4 mol of Fe is needed to react with → 3 mol of O₂, from stichiometry.

0.64 mol of Fe is needed to react with → ??? mol of O₂.

∴ The no. of moles of O₂ needed = (3 mol)(0.64 mol)/(4 mol) = 0.48 mol.

  • Finally, we can get the volume of oxygen using the information:

<em>It is known that 1 mole of any gas occupies 22.4 L at standard P and T (STP).</em>

<em></em>

<em><u>Using cross multiplication:</u></em>

1 mol of O₂ occupies → 22.4 L, at STP conditions.

0.48 mol of O₂ occupies → ??? L.

∴ The no. of liters of O₂ = (0.48 mol)(22.4 L)/(1 mol) = 10.752 L.

5 0
3 years ago
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