For the reaction shown, drsw the major(s) expected product.
1 answer:
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Answer:
Explanation:
Hello!
In this case, according to the reaction:
We can see there is a 4:2 mole ratio between chromium and chromium (III) oxide, this, for the given 56.2 g of chromium, the theoretical yield of the oxide product is computed down below:
Now, considering the 76.0-% yield for this reaction, the actual yield turns out:
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Answer:
C4H6
Explanation:
See attached table
Convert each of the masses into moles by dividing the mass by the molar mass of that element. That yields 3.83 moles of C and 6 moles of O. I rounded up the C to 4 moles to result in an empirical formula of C4H6
