The solution before dilution and after dilution contains same number of moles, and water is added for dilution.
Option B
<h3><u>Explanation:</u></h3>
Suppose before dilution, the solution contains x moles of KCl in Y liter of water. Now as the concentration got halved, then the solution contains x moles of KCl in 2Y kiters of solution. So the number of moles of KCl in the solution remained constant.
Again, as the solution is diluted to half of the concentration, water must have been added with the solution to make it dilute.
Answer:
Aldehydes are typically more reactive than ketones due to the following factors. ... The carbonyl carbon in aldehydes generally has more partial positive charge than in ketones due to the electron-donating nature of alkyl groups. Aldehydes only have one e- donor group while ketones have two.
Explanation:
Answer:
True
Explanation:
An orbital is is the space occupied by a pair of electrons. The maximum number of electrons in an orbital is 2.
The maximum number of electrons in in the orbitals are two.
For s-sublevel with one orbital we have two electrons
p-sublevel with three orbitals we have six electrons
d - sublevel with five orbitals we have ten electrons
f - sublevel with seven orbitals we have fourteen electrons
Each orbital can take a maximum of two electrons.
Answer:
The correct answer is C ions from the solute molecules have a strong attraction to the polar solvent molecules.
Explanation:
NaCl or Sodium chloride is an ionic compound which easily get dissolved in polar molecular compound such as water(H2O).
Both NaCl and H2O are polar compound because the atoms that forms NaCl and H2O have vast difference in their electronegativities.As a result the bonding electrons in both NaCl and H2O are not equally shared.
NaCl get dissolved in water molecules by dipole dipole interaction.
From the statement of Hess' law, the enthalpy of the reaction A---> C is +90 kJ
<h3>What is Hess' law?</h3>
Hess' law of constant heat summation states that for a multistep reaction, the standard enthalpy of reaction is always constant and is independent of the pathway or intermediate routes taken.
From Hess' law, the enthalpy change for the reaction A ----> C is calculated as follows:
A---> C = A ---> B + B ---> C
ΔH of A---> C = 30 kJ + 60 kJ
ΔH = 90 kJ
Therefore, the enthalpy of the reaction A---> C is +90 kJ
The above reaction A---> C can be shown in the enthalpy diagram below:
A -------------------> C (ΔH = +90 kJ)
\ /
\ / (ΔH = +60 kJ)
(ΔH = +30 J) \ /
> B
Learn more about enthalpy and Hess law at: brainly.com/question/9328637
