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telo118 [61]
3 years ago
14

Allura Red Moles

Engineering
1 answer:
Ivanshal [37]3 years ago
8 0

Answer:

Die of intoxication by water first

Explanation:

We assume that the weight of the man is 154.35 pounds which is 70 kg

LD50 water = 90g per kg

Maximum concentration = 90x70

= 6300grams

Convert grams to liters

6300/100

= 6.3 litres

From here we get amount of kool aid

6.3 x 1.97x10^-4

= 1.24x10^-3

= 1.24grams

1.24 grams is below 420 kool aid is lower than LD50 with about 6 grams for 1 kg (6x70kg = 420). So 420 is lethal dose. But 1.24 is less than this so the man has to die of water intoxication first.

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Sally made a diagram to show one way that Earth’s systems interact near a volcano.
ohaa [14]
We won’t be able to do it cuz we can’t draw on this app
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3 years ago
a resistor is made out of a long wire having a length L. Each end of the wire is attached to a termina of a battery providing a
Crank

Answer:

Option A

Solution:

As per the question:

Initially, voltage is V_{o}

Current is 'I' A

Length of the wire is L

Now,

We know that:

R = \frac{\rho L }{A}           (1)

where

\rho = resistivity\ of\ the wire

A = Cross sectional area of the wire

From eqn (1), if other things are taken to be constant, then

R ∝ L                 (2)

Thus

When the wire is cut into two reducing the length to \frac{L}{2}

Resistance, R' = \frac{R}{2}

Now, when these wires are connected as described, the connection is in parallel, therefore, the equivalent resistance of the two wires:

\frac{1}{R_{eq}} = \frac{1}{R'} + \frac{1}{R'}

\frac{1}{R_{eq}} = \frac{2}{R} + \frac{2}{R}

R_{eq} = \frac{R}{4}

Now, from Ohm's law:

I = \frac{V}{R}

Since, according to the question voltage V_{o} is constant, thus

I ∝ \frac{1}{R_{eq}}

I ∝ \frac{4}{R}

Thus

I becomes 4I

3 0
3 years ago
What are some advantages of generating electrical energy from tides instead of from fossil fuels
harina [27]

Answer:

Efficent at low speeds.

Explanation:

Since water is 1,000 times more dense than air, electricity can generated from tides much more efficiently at slower speeds than wind turbines can.

7 0
3 years ago
An automobile having a mass of 884 kg initially moves along a level highway at 68 km/h relative to the highway. It then climbs a
IRISSAK [1]

Answer:

ΔK.E. = - 142.72 kJ

Explanation:

mass = 884 kg

initial velocity = 68 km/h = 68 \times \frac {5}{18} = 18.89 m/s

final velocity = 0 m/s

height = 69 m

change in kinetic energy :

ΔK.E. = \dfrac{1}{2}m(v_f^2-v_i^2)

ΔK.E. =\dfrac{1}{2}\times 884 \times (0^2-18.89^2)

ΔK.E. =-142,716.05 J

ΔK.E. =-142.72 kJ

hence change in  kinetic energy of the automobile is  -142.72 kJ

6 0
3 years ago
A long cylindrical black surface fuel rod of diameter 25 mm is shielded by a surface concentric to the rod. The shield has diame
Elden [556K]

Answer:

surface temp of fuel rod = 678.85 K

Explanation:

Given data :

D1 = 25 mm

D2 = 50 mm

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T∞ = 300 k

hconv = 0.15 w/m^2.k

ε2 = 0.05

ε1 = 1

Determine energy at Q23

Q23 = Qconv + Qrad

attached below is the detailed solution

Insert given values into equation 1 attached below to obtain the surface temperature of the fuel rod ( T1 )

4 0
3 years ago
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