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Varvara68 [4.7K]
2 years ago
6

The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actu

al depth of the liquid in the tank?​
Physics
1 answer:
Juliette [100K]2 years ago
3 0

\orange{\underline{\huge{\bold{\textit{\green{\bf{QUESTION}}}}}}}

The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth of the liquid in the tank?

{\bold{\blue{GIVEN}}}

REFRACTIVE INDEX = 1.3

APPARENT DEPTH = 7.7 cm

{ \bold{\green{To  \: Find}}}

REAL DEPTH OF THE OBJECT.

{\red{FORMULA   \:  \: USED }}

Reflective  \:  Index  =  \frac{Real \:  Depth}{Apparent  \: Depth }

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Refractive Index = 1.3

Apparent Depth = 7.7 cm

Putting the values in the formula:-

Reflective  \:  Index  =  \frac{Real \:  Depth}{Apparent  \: Depth }  \\  \\ 1.3 =  \frac{Real \:  Depth}{7.7 \: cm}  \\ \\  1.3 \times 7.7 = Real \:  Depth \\  \\ 10.01 \:  \: cm = Real \:  Depth

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change in kinetic energy (K.E) = ¹/₂m(v² - u²)

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The change in kinetic energy (KE) of the car is more in the second case.

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