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coldgirl [10]
3 years ago
12

As shown in Fig. 4, an ideal gas of monatomic molecules expands from its initial state A to a state B through an isobaric proces

s and then further expands to a volume C. Find the work done by the gas, increase in internal energy, and the energy transferred by heat to the gas over the whole process​

Physics
1 answer:
cupoosta [38]3 years ago
7 0
The picture is very blurry
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UV radiaGon having a wavelength of 120 nm falls on gold metal, to which electrons are bound by 4.82 eV. What is the maximum kine
Solnce55 [7]

Answer:

K.E = 5.53 eV = 8.85 x 10⁻¹⁹ J

Explanation:

First we calculate the energy of photon:

E = hc/λ

where,

E = Energy of Photon = ?

h = Plank's Constant = 6.626 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength = 120 nm = 1.2 x 10⁻⁷ m

Therefore,

E = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(1.2 x 10⁻⁷ m)

E = (16.565 x 10⁻¹⁹ J)(1 eV/1.6 x 10⁻¹⁹ J)

E = 10.35 eV

Now, from Einstein's Photoelectric equation we know that:

Energy of Photon = Work Function + K.E of Electron

10.35 eV = 4.82 eV + K.E

K.E = 10.35 eV - 4.82 eV

<u>K.E = 5.53 eV = 8.85 x 10⁻¹⁹ J</u>

4 0
3 years ago
When spiking a volleyball, a player changes the velocity of the ball from 4.2m/s to -24m/s along a certain direction. If the imp
dedylja [7]

Answer:

The mass of the volleyball is 0.32 kg.

Explanation:

Given that,

Initial speed of the ball, u = 4.2 m/s

Final speed of the ball, v = -24 m/s

The impulse delivered to the ball by the player is -9.3 kg-m/s.

To find,

Mass of the volleyball.

Solution,

The change in momentum of the volleyball is equal to the impulse delivered to the ball. It is given by :

J=m(v-u)

m=\dfrac{J}{(v-u)}

m=\dfrac{-9.3\ kg-m/s}{(-24-4.2)\ m/s}

m = 0.32 kg

So, the mass of the volleyball is 0.32 kg.

5 0
3 years ago
There are six books in a stack, and each book weighs 5 N. The coefficient of static friction between the books is 0.2. With what
NikAS [45]

Answer:

b. 5 N

Explanation:

Each book weighs 5 N.  Therefore, five books weigh 25 N.  The friction force is:

Ff = Fn μ

Ff = (25 N) (0.2)

Ff = 5 N

3 0
3 years ago
Read 2 more answers
A cylindrical container closed of both end has a radius of 7cm and height of 6cm A.)find the total surface area of the container
Natalka [10]

Given:

A cylindrical container closed of both end has a radius of 7cm and height of 6cm.

Explanation:

A.) Find the total surface area of the container.

  • A = 2πrh + 2πr²
  • A = 2(3.14)(7)(6) + 2(3.14)(7 × 7)
  • A = 263.76 + 307.72
  • A = 571.48

B.) Find the volume of the container.

  • V = πr²h
  • V = (3.14)(7×7)(6)
  • V = 923.16

Not sure huhuness.

#CarryOnLearning

8 0
3 years ago
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An object with a mass of 9 kg weighs 14.4 N on the Moon. What is the
erma4kov [3.2K]

Answer:

1.6 m/s²

Explanation:

Weight equals mass times acceleration due to gravity.

F = mg

14.4 N = (9 kg) g

g = 1.6 m/s²

7 0
4 years ago
Read 2 more answers
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