Answer:
1➡️ this is the method of decomposition
2➡️ H2 and O2
3➡️ b
sorry if I am wrong
Answer:
at t=46/22, x=24 699/1210 ≈ 24.56m
Explanation:
The general equation for location is:
x(t) = x₀ + v₀·t + 1/2 a·t²
Where:
x(t) is the location at time t. Let's say this is the height above the base of the cliff.
x₀ is the starting position. At the base of the cliff we'll take x₀=0 and at the top x₀=46.0
v₀ is the initial velocity. For the ball it is 0, for the stone it is 22.0.
a is the standard gravity. In this example it is pointed downwards at -9.8 m/s².
Now that we have this formula, we have to write it two times, once for the ball and once for the stone, and then figure out for which t they are equal, which is the point of collision.
Ball: x(t) = 46.0 + 0 - 1/2*9.8 t²
Stone: x(t) = 0 + 22·t - 1/2*9.8 t²
Since both objects are subject to the same gravity, the 1/2 a·t² term cancels out on both side, and what we're left with is actually quite a simple equation:
46 = 22·t
so t = 46/22 ≈ 2.09
Put this t back into either original (i.e., with the quadratic term) equation and get:
x(46/22) = 46 - 1/2 * 9.806 * (46/22)² ≈ 24.56 m
Answer:
The tension in the string is equal to Ct
And the time t0 when the rension in the string is 27N is 3.6s.
Explanation:
An approach to solving this problem jnvolves looking at the whole system as one body by drawing an imaginary box around both bodies and taking summation of the forces. This gives F2 - F1 = Ct. This is only possible assuming the string is massless and does not stretch, that way transmitting the force applied across it undiminished.
So T = Ct
When T = 27N then t = T/C = 27/7.5 = 3.6s
The magnitude and direction of the net force is 9 newtons to the right ⇒ answer A
Explanation:
The net force is the vector sum of all the forces that act upon an object
If two forces are horizontal where,
> 
- They are in opposite direction
- Net force F =
-
in the direction of 
An object is acted upon by a force of 22 newtons to the right
and a force of 13 newtons to the left
We need to find the magnitude and direction of the net force
→
= 22 newtons to the right
→
= 13 newtons to the left
>
and they are in opposite direction
Substitute these values in the rule of the net force above
→ Net force F = 22 - 13 = 9
→ The direction of the net force is the same direction of the larger
force, the direction of the larger force is to the right
→ Net force is 9 newtons to the right
The magnitude and direction of the net force is 9 newtons to the right
Learn more:
You can learn more about the net force in brainly.com/question/4033012
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