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Airida [17]
3 years ago
15

Sound waves are moving across the room from the left toward the opening. What happens to the sound waves as they hit the wall wi

th an opening A Some of the sound waves refract off the wall, while other waves will move through the small opening and then spread out. This is called diffraction. B. Some of the sound waves will reflect off the wall, while others will difract trough the opening and spread out. C Most of the sound waves will reflect ofr the wall, while others will diffract through the opening and spread out. D. Most of the sound waves will reflect off the wall, while others will squeeze through the opening and then reflect again.
Physics
1 answer:
gladu [14]3 years ago
4 0

Answer: C is right

Explanation: Most of the sound waves are reflected back but waves passing opening will speread to all directions outside because of diffraction

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B : It will avoid the distortion from the atmosphere and give scientists more accurate data

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Is the arctic ocean larger than the indian ocean?
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You have arrived at the scene of a two car accident. You know the following pieces of information:
Pani-rosa [81]

The initial velocity of car 1 is 20 m/s to the right

The initial velocity of car 2 is zero

The final velocity of car 2 is 10 m/s to the right

Explanation:

We can solve the problem by using the law of conservation of momentum: the total momentum of the system must be conserved before and after the collision.

Therefore, we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 2000 kg is the mass of the first car

u_1 is the initial velocity of the first car

v_1 = 10 m/s is the final velocity of the first car (taking right as positive direction)

m_2 = 2000 kg is the mass of the second car

u_2 = 0 is the initial velocity of the second car

v_2 is the final velocity of the second car

We also know the initial momentum of car 1, which is

p_1 =40,000 kg m/s

And since momentum is the mass times the velocity, we find the initial velocity of car 1:

u_1 = \frac{p_1}{m_1}=\frac{40,000}{2,000}=20 m/s

with a positive sign, since the direction is to the right.

Now we can re-arrange the previous equation and solve for v2, the final velocity of car 2:

v_2 = \frac{m_1 u_1 -m_1 v_1}{m_2} = \frac{(2000)(20)-(2000)(10)}{2000}=10 m/s

And since the sign is positive, the direction is the same as the initial direction of car 1, so to the right.

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

brainly.com/question/2370982  

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#LearnwithBrainly

8 0
3 years ago
Interactive Solution 11.35 presents one method for modeling this problem. Multiple-Concept Example 8 also presents an approach t
shepuryov [24]

Answer:

a) Fi = 85.76 N

b) Fi = 87.8 N

Explanation:

Given:-

- Density of hydraulic oil, ρ = 804 kg/m^3

- The radius of input piston, ri = 0.00861 m

- The radius of output piston, ro = 0.141 m

Find:-

What input force F is needed to support the 23000-N combined weight of a car and the output plunger, when

(a) the bottom surfaces of the piston and plunger are at the same level

(b) the bottom surface of the output plunger is 1.10 m above that of the input plunger?

Solution:-

For part a.

- We see that both plungers are equal levels or there is no pressure due to elevation head. So we are only dealing with static pressure exerted by the hydraulic oil on both plungers to be equal. This part is an application of Pascal's Law:

                                  Pi = Po

                                  Fi / Ai = Fo / Ao

                                  Fi = Ai / Ao * Fo

                                  Fi = (ri/ro)^2 * Fo

                                  Fi = ( 0.00861 / 0.141 )^2 * 23000

                                  Fi = 85.76 N

For part b.

- We see that both plungers are at different levels so there is pressure due to elevation head. So we are only dealing with static pressure exerted by the hydraulic oil on both plungers plus the differential in heads. This part is an application of Bernoulli's Equation:

                                  Pi = Po + ρ*g*h

Where,                     h = Elevation head = 1.10m

                                  Fi = (ri/ro)^2 * Fo + ρ*g*h*π*ri^2

                                  Fi = 85.76 + (804*9.81*1.1*3.142*0.00861^2)

                                  Fi = 87.8 N

3 0
3 years ago
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