Answer:
Force is classified as a push or a pull
Explanation:
Answer:
Answer for A
Explanation:
F1=GmM/r1^2
If r2 becomes r2=5r
F2=GmM/(25r^2)
Multiply with 25 gives to maintain the same force
I.e.,25F2=F1
F2=G(25m)M/25r^2=F1
By the factor 25 would change to increase to same.
Answer:
The slope of a position-time graph can be calculated as:

where
is the increment in the y-variable
is the increment in the x-variable
We can verify that the slope of this graph is actually equal to the velocity. In fact:
corresponds to the change in position, so it is the displacement, 
corresponds to the change in time
, so the time interval
Therefore the slope of the graph is equal to

which corresponds to the definition of velocity.
Answer:
The rate at which radar must rotate is 0.335 rad/s.
Explanation:
Given that,
Velocity = 65 m/h = 29.0576 m/s
Angle = 15°
Suppose, the radius given by

We need to calculate the rate at which radar must rotate
Using formula of linear velocity


Where, v = velocity
r = radius
Put the value into the formula


Hence, The rate at which radar must rotate is 0.335 rad/s.