Ask question

Ask question

All categories

3 years ago

9

_one moleculetwo moleculesone moletwo moles of H2(g) reacts with _one moleculetwo moleculesone moletwo moles of

F2(g) to form _________one moleculetwo moleculesone moletwo moles of HF(g).

1 answer:

Arisa [49]3 years ago

8 0

Answer:

The reaction between hydrogen and fluorine.

Explanation:

The balanced chemical equation of the reaction is:

$H_2(g)+F_2(g)->2HF(g)$

From the balanced chemical equation, it is clear that:

1 mole of $H_2$ gas reacts with one mole of $F_2(g)$ and forms 2 moles of HF(g).

You might be interested in

A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a

Nady [450]

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

$q=mc\Delta T$

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

$q_{released}=q_{absorbed}\\
q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T$

The given mass of calorimeter has been, $m_{calorimeter}=1350\;\rm g$

The specific heat of the calorimeter has been, $c_{calorimeter}=5.82\;\rm J/g^\circ C$

The change in temperature of the calorimeter has been, $\Delta T=2.87^\circ \rm C$

Substituting the values for heat released:

$q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\
q_{released}=22,549.5\;\text J\\
q_{released}}=22.54\;\rm kJ$

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

6 0

3 years ago

H2SO4 is a strong acid because the first proton ionizes 100%. The Ka of the second proton is 1.1x10-2. What would be the pH of a

forsale [732]

Question options:

a) 2.05

b) 0.963

c) 0.955

d) 1.00

Answer:

b) 0.963

Explanation:

H2SO4→ HSO4- + H3O+

HSO4- + H2O ⇌ SO42- + H3O+

Construct ICE table:

HSO4- (aq) + H2O ⇌ SO42- (aq) + H3O+ (aq)

I 0.1 solid & 0 0.1

C -x liquid + x + x

E 0.1 - x are ignored x 0.1 + x

Calculate x

Ka = products/reactants

= $\frac{[SO42-] [H3O+]}{[HSO4-]}$

0.011 = $\frac{x (0.1 + x)}{0.1 - x}$

0.011 x (0.1 -x) = o.1x + x^2

0.0011 - 0.011 x - o.1x - x^2 = 0

0.0011 - 0.011 x - x^2 = 0

Use formula to solve for quadratic equation

x = ${ -b +,-\sqrt{b^2 - 4ac$ / 2a

a = -1, b = -0.111, c = 0.001

Solve for x

x = $\sqrt[-(-o.111)]{(-0.111)^2 - 4(-1) (0.0011) }$ / 2(-1)

x = 0.111 +,- $\sqrt{0.012321 + 0.0044}$ / -2

x = 0.111 +,- $\sqrt{0.016721}$ / -2

x = $\frac{0.111 +, - 0.1293}{-2}$

x = $\frac{0.111 + 0.1293}{-2}$ , x = $\frac{0.111 - 0.1293}{-2}$

x = $\frac{0.2403}{-2}$ , x = $\frac{0.0183}{-2}$

x = - 0.12015 , x = 0.00915

x cannot be negative, so

x = 0.00915 M

Calculate [H3O+]

[H3O+] = 0.1 M + x

[H3O+] = 0.1 M + 0.00915 M

[H3O+] = 0.10915 M

Clculate pH

pH = - log [ H3O+]

pH = - log [ 0.10915]

pH = 0.963

8 0

3 years ago

What is the wavelength (in meters) of an electromagnetic wave whose frequency is 2.63 × 1012 s−1?

aleksklad [387]

To find the wavelength of an electromagnetic wave for the given frequency can be determined by using the formulaSpeed=Wavelength x FrequencyWavelength=Speed/FrequencyGenerally Speed of the electromagnetic wave is 3x10^8 m/sBy substituting the values Wavelength=3x10^8 m/s / 2.63x10^12 s^-1Wavelength=1.14 x 10^-4 metres

4 0

3 years ago

1 L, 1000 mL, and 1000 cm are considered to be<br><br> EQUIVALENT or NON EQUIVALENT UNITS.

antoniya [11.8K]

Answer:

equivalent

Explanation:

hope it works

7 0

2 years ago

The label on a bottle shows the following information: C2H4O, molar mass 44.06 grams per mole. The formula must be:

Ivahew [28]

The formula can be empirical because the subscripts are reduced to the lowest fraction.

To check if this formula is also the molecular formula we can check by obtaining the molar mass of the compound it is equal to the given molar mass. Thus

12*2 + 4*1 + 16 = 44 g/mol

this is ~equal to the given molar mass thus the given equation can be both empirical and molecular.

5 0

3 years ago

Read 2 more answers